求救PHP获取IP的方法，用getenv(remote_addr);提示出错

Question

echo $_GET['REMOTE_ADDR'];另：错误提示是什么？？？？

Answer 1

你用phpinfo输出上面有很多环境变量。
有端口。有host

Answer 2

sorry~神仙是对的，我把SERVER写成了GET~~

Answer 3

unset($onlineip);  
if($_SERVER['HTTP_CLIENT_IP']){
$onlineip=$_SERVER['HTTP_CLIENT_IP'];}
elseif($_SERVER['HTTP_X_FORWARDED_FOR']){
$onlineip=$_SERVER['HTTP_X_FORWARDED_FOR']; }
else{$onlineip=$_SERVER['REMOTE_ADDR'];}echo $onlineip;