截取多个JSON的参数值遇到问题。

Question

json数据

Answer 1

$json = '[{"Name":"PM","Value":"224"},{"Name":"WD","Value":"25"},{"Name":"SD","Value":"34"}]';
$jsonArr = json_decode($json) ;
foreach ($jsonArr as  $value) {
if($value->Name == 'WD'){
echo $value->Value."<br />";
}
}

Answer 2

$s = '[{"Name":"PM","Value":"224"},{"Name":"WD","Value":"25"},{"Name":"SD","Value":"34"}]';
$t = array_filter(json_decode($s), function($v) { return $v->Name == 'WD'; });
echo current($t)->Value; //25