非常急,如能帮我.送100分!!

http://www.phpe.net/class/88.shtml
你要用就要看看源文件，里面有个例子的，不会PHP就要学嘛，到少要看得懂一点

解决方案 »

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做网站开发就不要怕学习，Script和Object的灵活性使开发变的容易，但是同时也程序的变化增加，一个开发好的程序到另外一台计算机上就可能不能运行。如果你已经找到了一个别人可以使用的程序，而在自己的计算机上不能使用，那么你还是应该静下心来把程序完整地看一遍，一般情况下，只要做非常小的改动就可以使用。
http://www.w8c.com/gb/images/php19a.zip这是老版本的,但能满足你的功能
新版本正在测试中,功能更强大,全面支持ZIP,TAR,GZ,TGZ文件的解压缩
if($action1){
?>
<html>
<head>
<title>File Upload Results</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
</head> <body bgcolor="#FFFFFF" text="#000000">
File
Upload Results <?
set_time_limit(60);
// make reasonably sure the script does not time out on large files
$path1 = dirname($PATH_TRANSLATED)."/upload/";
//print $PATH_TRANSLATED;
//print $path1." ";
// assign our path in a form PHP for Windows understands for($i=1;$i<3;$i++)
{
$temp1="file".$i;
$temp2="file".$i."_name";
$source=$$temp1;
$source_name=$$temp2;
// print $temp."=".$$temp." "; //print $file1_name;
//print $file2_name;
//exit; //*****************
//$source = $file1;
//$source_name = $file1_name;
print $source." ";
print $source_name;
//exit;
if(($source <> "none")&&($source <> ""))
{
// see if the file exists; non-existing file has name of "none"
if($error1 <> 1)
{
// no need to copy a file if directory not write-enabled
$dest = $path1.$source_name;
// append file name to our path if(copy($source,$dest)){
// copy the file from the temp directory to the upload directory, and test for success
echo "$source has been uploaded \n";
$imagesize = getimagesize($dest);
switch($imagesize[2])
{
case 0:
echo " Image is a unknown ";
unlink($dest);
exit;
case 1:
echo " Image is a GIF ";
echo "$dest has a width of $imagesize[0] ";
echo "$dest has a height of $imagesize[1] ";
$newname = $path1;
$newname .=$i.time() . ".gif";
if(copy($dest,$newname))
{
echo " GIF Rename Successful from $dest to $newname";
}else {
echo " GIF Rename Unsuccessful";
}
unlink ($dest);
break;
case 2:
echo " Image is a JPG ";
echo "$dest has a width of $imagesize[0] ";
echo "$dest has a height of $imagesize[1] ";
$newname = $path1;
$newname .=$i.time() . ".jpg";
if(copy($dest,$newname))
{
echo " JPG Rename Successful from $dest to $newname";
}else {
echo " JPG Rename Unsuccessful";
}
unlink ($dest);
break;
case 3:
echo " Image is a PNG ";
echo "$dest has a width of $imagesize[0] ";
echo "$dest has a height of $imagesize[1] ";
$newname = $path1;
$newname .=time() . ".png";
if(copy($dest,$newname))
{
echo " PNG Rename Successful from $dest to $newname";
}else {
echo " PNG Rename Unsuccessful";
}
unlink ($dest);
break;
}
}else {
echo "Upload directory not write-enabled\n";
// you need to write-enable the upload directory
$error1 = 1; // set flag
}
}
unlink($source);
// delete the file from the temp directory
} ?>
<image src="upload/<? print basename($newname)?>">
<?
} //end for
?>
 <a href="fup.php">Back</a>

</body>
</html> <?
}
else { ?> <html>
<head>
<title>File Upload</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
</head> <body bgcolor="#FFFFFF" text="#000000">
File
Upload 
If your browser is upload-enabled, you will see "Browse"
(Netscape, Internet Explorer) or ". . ." (Opera) buttons below.
Use them to select file(s) to upload, then click the "Upload"
button. After the files have been uploaded, you will see a results screen. 
<form method="post" enctype="multipart/form-data" action="fup.php">
<input type="hidden" name="MAX_FILE_SIZE" value="800000">
<input type="hidden" name="action1" value="1">
File 1: <input type="file" name="file1" size="30"> 
File 2: <input type="file" name="file2" size="30"> 
 
<input type="submit" value="Upload">
</form>

</body>
</html> <? } ?>
用ftp软件可以改，选择需要改的文件夹在远端窗口，右击，拿cuteftp来说，有属性选项，可以改为777
留下你MAIL，我给你个多文件FTP上传类（偶自己写的，可能水平不高，不过绝对能用）
已经发给你了，里面有一个DEMO
你自己看吧
FTP类支持自定义上传的文件类型，大小，保存到的目录，重命名等，对文件个数没限制，不过要有服务器的可写权限