function check_user($nicker,$password,$level=2) { global $ndb;
<? include("db_mysql.inc"); $db = new db_Sql;//第3行 $db->connect("borrow","localhost","root",""); function check_user($nicker,$password,$level=2) { global $db; if($nicker=="") return 0; $sql = "select password from user_info where nicker='$nicker'"; $row = $db->query($sql);//第10行 if($row->next_record() == $password) return 1; else return 0; } ?>
你的自定义函数中无法识别类$db,你可以这样改进 方案一: <? include("db_mysql.inc"); $db = new db_Sql;//第3行 $db->connect("borrow","localhost","root",""); function check_user($nicker,$password,$level=2) { gloable &db; //改进后增进的指令行 if($nicker=="") return 0; $sql = "select password from user_info where nicker='$nicker'"; $row = $db->query($sql);//第10行 if($row->next_record() == $password) return 1; else return 0; } ?>方案二 <? include("db_mysql.inc"); $db = new db_Sql;//第3行 $db->connect("borrow","localhost","root",""); function check_user($nicker,$password,$level=2,$db) //改进后将$db作为参数传入函数内 { if($nicker=="") return 0; $sql = "select password from user_info where nicker='$nicker'"; $row = $db->query($sql);//第10行 if($row->next_record() == $password) return 1; else return 0; } ?>
<? include("db_mysql.inc"); $db = new db_Sql;//第3行 $db->connect("borrow","localhost","root",""); function check_user($nicker,$password,$level=2) { global $db; if($nicker=="") return 0; $sql = "select password from user_info where nicker='$nicker'"; $row = $db->query($sql);//第10行 if($row->next_record() == $password)//第11行 return 1; else return 0; } ?>按照这个方案改了后,在第11行又除了问题,Call to a member function on a non-object ,这又是什么问题呀? 哎,我这是第一次用类来做项目,就遇到这个问题,真不习惯。
<? include("db_mysql.inc"); $db = new db_Sql;//第3行 $db->connect("borrow","localhost","root",""); function check_user($nicker,$password,$level=2) { global $db; if($nicker=="") return 0; $sql = "select password from user_info where nicker='$nicker'"; $db->query($sql);//第10行 if($db->next_record() == $password)//第11行 return 1; else return 0; } ?>
$row = $ndb->query($sql);
{
global $ndb;
include("db_mysql.inc");
$db = new db_Sql;//第3行
$db->connect("borrow","localhost","root","");
function check_user($nicker,$password,$level=2)
{
global $db;
if($nicker=="")
return 0;
$sql = "select password from user_info where nicker='$nicker'";
$row = $db->query($sql);//第10行
if($row->next_record() == $password)
return 1;
else
return 0;
}
?>
方案一:
<?
include("db_mysql.inc");
$db = new db_Sql;//第3行
$db->connect("borrow","localhost","root","");
function check_user($nicker,$password,$level=2)
{
gloable &db; //改进后增进的指令行
if($nicker=="")
return 0;
$sql = "select password from user_info where nicker='$nicker'";
$row = $db->query($sql);//第10行
if($row->next_record() == $password)
return 1;
else
return 0;
}
?>方案二
<?
include("db_mysql.inc");
$db = new db_Sql;//第3行
$db->connect("borrow","localhost","root","");
function check_user($nicker,$password,$level=2,$db) //改进后将$db作为参数传入函数内
{
if($nicker=="")
return 0;
$sql = "select password from user_info where nicker='$nicker'";
$row = $db->query($sql);//第10行
if($row->next_record() == $password)
return 1;
else
return 0;
}
?>
include("db_mysql.inc");
$db = new db_Sql;//第3行
$db->connect("borrow","localhost","root","");
function check_user($nicker,$password,$level=2)
{
global $db;
if($nicker=="")
return 0;
$sql = "select password from user_info where nicker='$nicker'";
$row = $db->query($sql);//第10行
if($row->next_record() == $password)//第11行
return 1;
else
return 0;
}
?>按照这个方案改了后,在第11行又除了问题,Call to a member function on a non-object ,这又是什么问题呀?
哎,我这是第一次用类来做项目,就遇到这个问题,真不习惯。
include("db_mysql.inc");
$db = new db_Sql;//第3行
$db->connect("borrow","localhost","root","");
function check_user($nicker,$password,$level=2)
{
global $db;
if($nicker=="")
return 0;
$sql = "select password from user_info where nicker='$nicker'";
$db->query($sql);//第10行
if($db->next_record() == $password)//第11行
return 1;
else
return 0;
}
?>