求函数，100分，快来啊～～～～

Question

用ereg(/[\w]{0,}/)判断字符串只含有0～9数字、a～z、A～Z字母

Answer 1

/[a-zA-Z0-9]{0,}/判断字符串只含有0～9数字、a～z、A～Z字母

Answer 2

用ereg(/^[\w]|@|[0-9a-zA-Z]|.|[a-z]?$/)判断字符串是否是合法的邮件地址

Answer 3

ereg("^(.+)@(.+)\\.(.+)$",$email,$all)

Answer 4

ereg("^\w+((-\w+)|(\.\w+))*\@[A-Za-z0-9]+((\.|-)[A-Za-z0-9]+)*\.[A-Za-z0-9]{2,3}$",$email,$all)

Answer 5

function check_email($email = "") {     $email = preg_replace( "#[\n\r\*\'\"<>&\%\!\(\)\{\}\[\]\?\\/]#", "", $email );
    
     if ( preg_match( "/^.+\@(\[?)[a-zA-Z0-9\-\.]+\.([a-zA-Z]{2,4}|[0-9]{1,4})(\]?)$/", $email) )
     {
     return $email;
     }
     else
     {
     return FALSE;
     }
}

Answer 6

<?PHP
$email="[email protected]";
if(ereg("^[a-zA-Z0-9]+@[a-zA-Z0-9]+(\.[a-zA-Z0-9]+)+$",$email))
echo $email."正确<br>";
else
echo $email."不正确<br>";
?>

Answer 7

1.
$email="[email protected]";
if(preg_match("/^\w+@[a-z0-9]+(\.[a-z0-9]+){1,5}$/i",$email))
echo $email."合法";
else
echo $email."不合法";
2.
$str="adsfadsf2134";
if(preg_match("/^[0-9a-z]+$/i",$str)){
echo "合法";
}else{
echo "不合法";
}

Answer 8

用正则表达式，PHP帮助里有例子，还是自己看懂了才是最佳效果

Answer 9

<?PHP
$email="[email protected]";
if(ereg("^[a-zA-Z0-9]+@[a-zA-Z0-9]+(\.[a-zA-Z0-9]+)+$",$email))
echo $email."正确<br>";
else
echo $email."不正确<br>";
?>就可以了....我在用...