PHPUnit如何mock函数内部实例化的对象

Question

phpunitmock

Answer 1

class cash 这个已经定义好了吗，还是没有定义？

Answer 2

在《修改代码的艺术》一书中找到了答案:class sendMsg{
    protected function cash(){
         return new cash()
    }
    public function send(){
          $cash = $this->cash();
          $isCashed = $cash->isCashed();
          return $isCashed;
         //do something
    }
}
//将外部依赖抽离到单独的函数 然后测试的时候创建一个子类
class sendMsgExt extend sendMsg{
        protected $cash;
        public function setCash($cash){
                return $this->cash = $cash;
        }
        protected function cash(){
            return $this->cash;
        }
}
//测试的时候 实例化子类并通过setCash将mock出来的cash注入进来
class sendMsgTest extension PHPUnit_Framework_TestCase{
       
       public function testSend(){
             $sendMsg = new sendMsgExt();
             $mockCash = $this->mock('cash');
             $mockCash->expects($this->any())->method("isCashed")->will($this->returnValue(1));
              $sendMsg->setCash($mockCash);
              $this->assertEquals(1,$sendMsg->send());
      }
}