图片和二进制之间的转换 图片 二进制 解决方案 » 免费领取超大流量手机卡,每月29元包185G流量+100分钟通话, 中国电信官方发货 估计你前面有echo或其他输出影响了,在echo($data[2]); 前加一句 ob_clean(); 试试。 写了一个完整的例子,可以参考下。数据表结构CREATE TABLE `photo` ( `id` int(10) unsigned NOT NULL auto_increment, `type` varchar(100) NOT NULL, `photo` mediumblob NOT NULL, PRIMARY KEY (`id`)) upload_image_todb.php<?php$conn=@mysql_connect("数据库ip","帐号","密码") or die(mysql_error());@mysql_select_db('数据库名',$conn) or die(mysql_error());$action = isset($_REQUEST['action'])? $_REQUEST['action'] : '';if($action=='add'){ $image = mysql_escape_string(file_get_contents($_FILES['photo']['tmp_name'])); $type = $_FILES['photo']['type']; $sqlstr = "insert into photo(type,photo) values('".$type."','".$image."')"; @mysql_query($sqlstr) or die(mysql_error()); header('location:upload_image_todb.php');}elseif($action=='show'){ $id = isset($_GET['id'])? intval($_GET['id']) : 0; $sqlstr = "select * from photo where id=$id"; $query = mysql_query($sqlstr) or die(mysql_error()); $thread = mysql_fetch_assoc($query); if($thread){ header('content-type:'.$thread['type']); echo $thread['photo']; exit(); }}else{?><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"><html> <head> <meta http-equiv="content-type" content="text/html; charset=utf-8"> <title> upload image to db </title> </head> <body> <form name="form1" method="post" action="upload_image_todb.php" enctype="multipart/form-data"> <p>图片:<input type="file" name="photo"></p> <p><input type="hidden" name="action" value="add"><input type="submit" name="b1" value="提交"></p> </form><?php $sqlstr = "select * from photo order by id desc"; $query = mysql_query($sqlstr) or die(mysql_error()); $result = array(); while($thread=mysql_fetch_assoc($query)){ $result[] = $thread; } foreach($result as $val){ echo '<p><img src="upload_image_todb.php?action=show&id='.$val['id'].'&t='.time().'"></p>'; }?> </body></html><?php}?> 你这个是 JFIF 格式的图片吧?没有几个浏览器能支持的 上传了jpg和png的图片,效果也还是一样,加载不出 在echo($data[2]); 前加一句 ob_clean(); 试试。這個試過了嗎? 可以把文件二進制的base64_encode後的字符串發出來嗎?echo base64_encode(file_get_contents('xxx.jpg'));我測試下是不是圖片有問題。 mysql多个关键字的查询 求解 php学习资源 为什么我这样子的替换会出错呢?我不知道哪里错了 PHP: utf-8 -> gb2312 丢字问题.. PHP 基础问题!~ 使用 pear包里的mail类发送邮件,发件人怎么用这样的格式:发件人名称 <发件人邮件地址>,如 老张 <[email protected]> ??? 想问下大牛怎么看源代码来实习 我用mcrypt加密库的函数总是提示mcrypt_get_block_size函数错误 新手求支招 YII 框架上如何调用控制台执行php文件 CI框架下用存储过程后不能再进行其他查询 php正则替换问题
在echo($data[2]); 前加一句 ob_clean(); 试试。
数据表结构CREATE TABLE `photo` (
`id` int(10) unsigned NOT NULL auto_increment,
`type` varchar(100) NOT NULL,
`photo` mediumblob NOT NULL,
PRIMARY KEY (`id`)
)
upload_image_todb.php<?php
$conn=@mysql_connect("数据库ip","帐号","密码") or die(mysql_error());
@mysql_select_db('数据库名',$conn) or die(mysql_error());$action = isset($_REQUEST['action'])? $_REQUEST['action'] : '';if($action=='add'){
$image = mysql_escape_string(file_get_contents($_FILES['photo']['tmp_name']));
$type = $_FILES['photo']['type'];
$sqlstr = "insert into photo(type,photo) values('".$type."','".$image."')";
@mysql_query($sqlstr) or die(mysql_error()); header('location:upload_image_todb.php');}elseif($action=='show'){ $id = isset($_GET['id'])? intval($_GET['id']) : 0;
$sqlstr = "select * from photo where id=$id";
$query = mysql_query($sqlstr) or die(mysql_error());
$thread = mysql_fetch_assoc($query);
if($thread){
header('content-type:'.$thread['type']);
echo $thread['photo'];
exit();
}
}else{
?>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8">
<title> upload image to db </title>
</head> <body>
<form name="form1" method="post" action="upload_image_todb.php" enctype="multipart/form-data">
<p>图片:<input type="file" name="photo"></p>
<p><input type="hidden" name="action" value="add"><input type="submit" name="b1" value="提交"></p>
</form><?php
$sqlstr = "select * from photo order by id desc";
$query = mysql_query($sqlstr) or die(mysql_error());
$result = array();
while($thread=mysql_fetch_assoc($query)){
$result[] = $thread;
}
foreach($result as $val){
echo '<p><img src="upload_image_todb.php?action=show&id='.$val['id'].'&t='.time().'"></p>';
}
?> </body>
</html>
<?php
}
?>
没有几个浏览器能支持的
echo base64_encode(file_get_contents('xxx.jpg'));我測試下是不是圖片有問題。