function URLhtml($url)
{
#-php后缀匹配-#
$pat="php";
$url02=ereg_replace($pat,"html","\\2");
#-php后缀匹配-#
return $url02;
} ob_end_clean();
ob_start();
include('index.php');
$length = ob_get_length();
$buffer = ob_get_contents();
$pat = '/<a(.*?)href="(.*?)"(.*?)>(.*?)<\/a>/i';
$buffer=preg_replace($pat,URLhtml("\\2"),$buffer);
echo $buffer;上面那段代码为什么只可以找得到URL切不会函数匹配???
{
#-php后缀匹配-#
$pat="php";
$url02=ereg_replace($pat,"html","\\2");
#-php后缀匹配-#
return $url02;
} ob_end_clean();
ob_start();
include('index.php');
$length = ob_get_length();
$buffer = ob_get_contents();
$pat = '/<a(.*?)href="(.*?)"(.*?)>(.*?)<\/a>/i';
$buffer=preg_replace($pat,URLhtml("\\2"),$buffer);
echo $buffer;上面那段代码为什么只可以找得到URL切不会函数匹配???
我见DZ论坛的ubb也用了这种替换模式,他用了class类...不过不是用不用类的问题,是不是哪一步错了??
<?php
// 此文本是用于 2002 年的,
// 现在想使其能用于 2003 年
$text = "April fools day is 04/01/2002\n";
$text.= "Last christmas was 12/24/2001\n"; // 回调函数
function next_year($matches) {
// 通常:$matches[0] 是完整的匹配项
// $matches[1] 是第一个括号中的子模式的匹配项
// 以此类推
return $matches[1].($matches[2]+1);
} echo preg_replace_callback(
"|(\d{2}/\d{2}/)(\d{4})|",
"next_year",
$text); // 结果为:
// April fools day is 04/01/2003
// Last christmas was 12/24/2002
?>