php写好后台代码返回给前台jquery easyui 的datagrid中， kindeditor如何获取datagrid里面的值


 <script>
        KindEditor.ready(function(K) {
            var editor1 = K.create('textarea[name="content"]', {
                cssPath : '../kindeditor/plugins/code/prettify.css',
                uploadJson : '../kindeditor/upload/upload_json.php',
                fileManagerJson : '../kindeditor/upload/file_manager_json.php',
                allowFileManager : true,
                afterCreate : function() {
                    var self = this;
                    K.ctrl(document, 13, function() {
                        self.sync();
                        K('form[name=fm]')[0].submit();
                    });
                    K.ctrl(self.edit.doc, 13, function() {
                        self.sync();
                        K('form[name=fm]')[0].submit();
                    });
                }
            });
            prettyPrint();
        });
    </script> <div id="dlg" class="easyui-dialog" style="width:800px;height:440px;padding:10px 20px" closed="true">
        <div class="ftitle">新闻</div>
        <form id="fm" method="post" enctype="multipart/form-data" novalidate>
            <textarea name="content" style="width:700px;height:200px;visibility:hidden;"></textarea>
        </form>
</div>应该如何把easyui 中 datagrid获取到的数据，加入到 kindeditor中？