jquery ajax

Question

$(document).ready(function(){
$("#bn1").click(function(){

htmlobj=$.ajax({url:"controller/mycontroller.php",
async:true,
type:'POST',
data:{
name:$("#login_1.name").val() ,
passwo:$("#login_1.password").val() ,
flag:'1',

}
});
alert(htmlobj.responseText);
$("#myDiv").html(htmlobj.responseText); });
}); alert(htmlobj.responseText);提示undefined；

Answer 1

ajax是异步，要用回调方式
$(document).ready(function(){
    $("#bn1").click(function(){        $.ajax({url:"controller/mycontroller.php",
            async:true,
            type:'POST',
            data:{
                name:$("#login_1.name").val() ,
                passwo:$("#login_1.password").val() ,
                flag:'1',
            },
            dataType: "json",
            success: function(htmlobj){
                alert(htmlobj.responseText);
                $("#myDiv").html(htmlobj.responseText);
            }
        });    });
});