怎么才能取到我想要的属性？

Question

log输出代码:
$this->log->debug("@@@@@@@@@@@@@@@@@@@@@:" . print_r($member,true));log输出内容:
@@@@@@@@@@@@@@@@@@@@@:Member Object
(
    [apiRequest:Member:private] => ApiRequest Object
        (
            [log:protected] => Logger Object
                (
                    [name:Logger:private] => ApiRequest
                    [logLevel:Logger:private] => DEBUG
                    [levelList:Logger:private] => Array
                        (
                            [TRACE] => 1
                        )
                )
            [history:protected] => Array
                (
                )
            [additionalHeader:ApiRequest:private] => 
        )
    [domain:Member:private] => https
    [userId:Member:private] => 1111
    [memberId:Member:private] => aabbcc
    [userIdFilePath:Member:private] => /home/aaa.dat
)问题:
我想把memberId的aabbc取出来请问怎么写啊。
下面这样写都不行
$member[memberId:Member:private]
$member -> memberId

Answer 1

memberId是private的 外面看不到