<td width="792" height="29" colspan="3"><label> <select
                        name="select" style="width: 150px;">
                        <?php
                        while($row=mysql_fetch_array($query)){
                            ?>
                            <option>
                            <?php echo $row[types]?>
                            </option>
                            <?php
                        }
                     ?> 我想在取个id的值 保存到另外一个表,但在while里加了隐藏表单 格式就乱了, 请问怎么才能在取个id的值??? 请求解答 非常感谢

解决方案 »

  1.   

     <td width="792" height="29" colspan="3"><label> <select
                            name="select" style="width: 150px;">
                            <?php
                            while($row=mysql_fetch_array($query)){
                                ?>
                                <option value="<?php echo $row['id']?>">
                                <?php echo $row['types']?>
                                </option>
                                <?php
                            }
                         ?> 
      

  2.   

    option有个value被你搞掉了呵呵
      

  3.   

     一年没开发了 好多东西忘了,把问题想的太复杂化了 第一次用Php 呵呵 谢谢