<?$n1 =date("d");$fh = opendir ("./a/");
$q = readdir ($fh);while ($q){
$b1 = substr ($q,-10,2);if ($n1 == $b1){
echo "$q";}$q = readdir ($fh);
}
?>
我现在想用fopen打开$q所表示的文件,请问怎么打开啊 谢谢
$q = readdir ($fh);while ($q){
$b1 = substr ($q,-10,2);if ($n1 == $b1){
echo "$q";}$q = readdir ($fh);
}
?>
我现在想用fopen打开$q所表示的文件,请问怎么打开啊 谢谢
$dh = opendir ("./");while ($file = readdir($dh)){
$c = substr($file,-10,2);
if ($c == $n1) { // 打开,并且读取文件内容
$handle = fopen($file);
$contents = fread($handle, filesize ($filename));
fclose($handle);
}
}
closedir($dh);
$n1 =date("d");
$dh = opendir ("./a/");while ($file = readdir($dh)){
$c = substr($file,-10,2);
if ($c == $n1) { // 打开,并且读取文件内容
$handle = fopen($file);
$contents = fread($handle, filesize ($filename));
fclose($handle);
}
}
closedir($dh);
?>
怎么结果是这样的啊 谁能帮忙改改么 谢谢
Warning: fopen() expects at least 2 parameters, 1 given in /var/www/html/lyr/bb.php on line 8Warning: fread(): supplied argument is not a valid stream resource in /var/www/html/lyr/bb.php on line 9Warning: fclose(): supplied argument is not a valid stream resource in /var/www/html/lyr/bb.php on line 10
$handle = fopen ($filename, "r");
$contents = fread ($handle, filesize ($filename));
fclose ($handle);
$handle = fopen ("/home/rasmus/file.txt", "r");
$handle = fopen ("/home/rasmus/file.gif", "wb");
$handle = fopen ("http://www.example.com/", "r");
$handle = fopen ("ftp://user:[email protected]/somefile.txt", "w");
?>
fopen要两个参数,你只给了一个,第二个是打开文件的模式。