echo 输出 单双引号问题

Question

echo "<img src='a.jpg' width='600' style='margin-top:5px;'onerror="this.src='http://www.lanrentuku.com/images/logo.jpg'"/>";
后面onerror 里面需要双引号套单引号  怎么写 ！高手帮忙写下

Answer 1

<?php 
echo "<img src='a.jpg' width='600' style='margin-top:5px;'onerror=\"this.src='http://www.lanrentuku.com/images/logo.jpg'\"/>";
?>

Answer 2

echo <<<EOF
Your content here.
EOF;