两个php文件,其中一个提交上传文件的表单:index.php:
<form method="post" action="upload.php" enctype="multipart/form-data" target="up_frm">
<input type="file" name="upload" id="upload" style="font-family:arial;width:271px;height:20px">
<input type="submit" id="submit">
</form>
另一个是upload.php:$filename="NULL";
if ($_FILES["upload"]["error"] > 0){
$filename="Error: ".$_FILES["upload"]["error"];
}else{
if(is_uploaded_file($_FILES["upload"]["tmp_name"])){
$arrname=explode(".",strval($_FILES["upload"]["name"]));
$filename=array_pop($arrname);
$filename=array_pop($arrname).".".$filename;
move_uploaded_file($_FILES["upload"]["tmp_name"],"./temp/upload/".$filename);
echo "<script language=\"JavaScript\" type=\"text/JavaScript\"> var filename='".$filename."';document.cookie="filename"+'='+filename+";";alert(filename);</script>";
}else{
$filename='FLASE';
}
}
现在的问题是,我要在index.php里处理这个文本文件(打开并读出其中内容)。那么,如何将upload.php里的filename传递给index.php呢?请达人指教,十分感谢!
<form method="post" action="upload.php" enctype="multipart/form-data" target="up_frm">
<input type="file" name="upload" id="upload" style="font-family:arial;width:271px;height:20px">
<input type="submit" id="submit">
</form>
另一个是upload.php:$filename="NULL";
if ($_FILES["upload"]["error"] > 0){
$filename="Error: ".$_FILES["upload"]["error"];
}else{
if(is_uploaded_file($_FILES["upload"]["tmp_name"])){
$arrname=explode(".",strval($_FILES["upload"]["name"]));
$filename=array_pop($arrname);
$filename=array_pop($arrname).".".$filename;
move_uploaded_file($_FILES["upload"]["tmp_name"],"./temp/upload/".$filename);
echo "<script language=\"JavaScript\" type=\"text/JavaScript\"> var filename='".$filename."';document.cookie="filename"+'='+filename+";";alert(filename);</script>";
}else{
$filename='FLASE';
}
}
现在的问题是,我要在index.php里处理这个文本文件(打开并读出其中内容)。那么,如何将upload.php里的filename传递给index.php呢?请达人指教,十分感谢!
print_r($_FILES['file']);
index.php里有ajax,处理另一部分数据的。
我开始的index.php是这样的:<?php
$filename="NULL";
if ($_FILES["upload"]["error"] > 0){
$filename="Error: ".$_FILES["upload"]["error"];
}else{
if(is_uploaded_file($_FILES["upload"]["tmp_name"])){
$arrname=explode(".",strval($_FILES["upload"]["name"]));
$filename=array_pop($arrname);
$filename=array_pop($arrname).".".$filename;
move_uploaded_file($_FILES["upload"]["tmp_name"],"./temp/upload/".$filename);
}else{
$filename='FALSE';
}
echo "<script language=\"JavaScript\" type=\"text/JavaScript\"> var filename='".$filename."';alert(filename);</script>";
}
?><form method="post" action="" enctype="multipart/form-data" target="up_frm">
<input type="submit" value="Compare" class="btn"/>
<br><b>Or upload file:<br></b>
<input type="file" name="upload" id="upload" style="font-family:arial;width:271px;height:20px">
</form><iframe name=up_frm style="display:none">
</iframe><script type="text/javascript">
alert(filename);
</script>
在php里的那段js的alert确实是filename。
可是最下面的filename始终是NULL。谢谢指教!
我把index.php改成<body>
<?php
$filename=$_GET['filename'];
echo $filename;
?>
<form method="post" action="upload.php" enctype="multipart/form-data" target="up_frm">
<br><b>Or upload file:<br></b>
<input type="file" name="upload" id="upload" style="font-family:arial;width:271px;height:20px">
<input type="submit" value="Compare"/>
</form><iframe name=up_frm style="display:none">
</iframe></body>
</html>把upload.php改成:<?php
header('Location: index.php?filename='.$filename);
$filename="NULL";
if ($_FILES["upload"]["error"] > 0){
$filename="Error: ".$_FILES["upload"]["error"];
}else{
if(is_uploaded_file($_FILES["upload"]["tmp_name"])){
$arrname=explode(".",strval($_FILES["upload"]["name"]));
$filename=array_pop($arrname);
$filename=array_pop($arrname).".".$filename;
move_uploaded_file($_FILES["upload"]["tmp_name"],"./temp/upload/".$filename);
}else{
$filename='FLASE';
}
}
?>
弱弱的问,是这样吗?
在最后
我放到最后了。可是index那个页面还是没有输出filename。