function checkUsername($username){
$sql="select * from blogusers where username='".$username."'";
$result=mysql_query($sql);
if($rs=mysql_fetch_object($result)){
return 1;
}else{
return 0;
}
}就这个方法 老是提示mysql_fetch_object有错....还有
$sql = "select * from stories where 1='1'".$keyword." order by storyID desc limit $limitFrom,$pagelist";
$result=mysql_query($sql);
while($rs=mysql_fetch_object($result))
{}
这个是总是提示mysql_fetch_object有错,我完全不知道 怎么改...错误提示是Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in D:\www\pan\index.php on line 58
$sql="select * from blogusers where username='".$username."'";
$result=mysql_query($sql);
if($rs=mysql_fetch_object($result)){
return 1;
}else{
return 0;
}
}就这个方法 老是提示mysql_fetch_object有错....还有
$sql = "select * from stories where 1='1'".$keyword." order by storyID desc limit $limitFrom,$pagelist";
$result=mysql_query($sql);
while($rs=mysql_fetch_object($result))
{}
这个是总是提示mysql_fetch_object有错,我完全不知道 怎么改...错误提示是Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in D:\www\pan\index.php on line 58
blogusers 数据库名?
username 有这个字段?
最主要的是$username是什么?