请问取明天的日期值怎么弄?

Question

echo date('Y-m-j');这是今天的日期, 请问明天和后天的怎么取?还有今天是星期几用$weekarray=array("日","一","二","三","四","五","六");  
echo "星期".$weekarray[date("w")]; 可以取得, 那么明天和后天应该怎么取呢?谢谢,本人刚学, 麻烦指教

Answer 1

date("Y-m-d",mktime("","","",date("m"),date("d"),date("Y")))mktime函数

Answer 2

写错了，这个
$date = date("Y-m-d",mktime(0,0,0,date('m'),date('d')+1,date('Y')));

Answer 3

楼上的意思是明天: date("Y-m-d",mktime(0,0,0,date("m"),date("d")+1,date("Y")));
后天: date("Y-m-d",mktime(0,0,0,date("m"),date("d")+2,date("Y")));是吗?

Answer 4

明天 ：date("Y-m-d",time()+3600*24*1)
后天 ：date("Y-m-d",time()+3600*24*2)

Answer 5

星期用$weekarray[date("w")+1; 对吗?

Answer 6

echo date("Y-m-d", strtotime("+1 day"));

Answer 7

<?php
class a
{
function a()
{
$d=getdate();
$day=$d[mday];//得出今天是几号$week=$d[weekday];//得出今天是星期几
//echo $week;
switch($week)
{
case"monday";
$x=$day;
$y=$day-6;
echo "这周的星期一是".$x."星期日是".$y;
break;
case"Tuesday";
$x=$day-1;
$y=$day-5;
echo"这周的星期一是".$x."星期日是".$y;
break;
case"Friday";
$x=$day-2;
$y=$day-4;
echo"这周的星期一是".$x."星期日是".$y; 
break;
}
}
}
$c=new a;
?>

Answer 8

date('Y-m-d',time()+3600*24)  或者 date('Y-m-d' strtotime(+1 day))