php如何用过滤以下内容？

Question

字符的内容是一个时间，不知为什么多了一个换行和这么长的空白(空白的长度也不一样，用trim过滤不了)：20 
                08-07-18

Answer 1

$str='20 
                08-07-18 <br>';
echo preg_replace( '|(20)[\s\n]+?(08-)|ism', '$1$2', $str);

Answer 2

简化点的
$str='20 
                08-07-18 <br>';
echo preg_replace( '|(20)\s+?(08-)|ism', '$1$2', $str);

Answer 3

preg_replace("/(\d{2})\s*(\d{2}-\d{2}-\d{2})/","\\1\\2",$str);

Answer 4

$str='20 
                08-07-18 <br>';
preg_match( "/[0-9-]/", $str, $reu);
echo $reu[0][0];

Answer 5

错了，看错了
这个是对的
<?php
$str='20 
                08-07-18 <br>'; 
preg_match_all( "/[0-9-]/", $str, $reu); 
//print_r($reu); 
$strs="";
//echo count($reu[0]);
for ($i=0;$i<count($reu[0]);$i++)
{
$strs.=$reu[0][$i];
}
echo $strs;
?>

Answer 6

preg_replace("/\s/", "", $str);

Answer 7

preg_replace("|(\d{2})\s+(\d{2}-\d{2}-\d{2})|ism","$1$2",$str);

Answer 8

  1 <?php
  2 
  3 
  4 $str='20
  5                 08-07-18 <br>';
  6 
  7 preg_match('|[0-9]+\s+([^<]+)<br>|si',$str,$arr);
  8 $strr   =       $arr[1];
  9 echo '20'.$strr;
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Answer 9

1 <?php
  2
  3
  4 $str='20
  5                08-07-18 <br>';
  6
  7 preg_match('|[0-9]+\s+([^<]+) <br>|si',$str,$arr);
  8 $strr  =      $arr[1];
  9 echo '20'.$strr;
~