貌似这个问题不是前几天才有人问过了吗
手册的iconv部分不是有的吗function unescape($str) {
$str = rawurldecode($str);
preg_match_all("/(?:%u.{4})|&#x.{4};|&#\d+;|.+/U",$str,$r);
$ar = $r[0];
//print_r($ar);
foreach($ar as $k=>$v) {
if(substr($v,0,2) == "%u")
$ar[$k] = iconv("UCS-2","UTF-8",pack("H4",substr($v,-4)));
elseif(substr($v,0,3) == "&#x")
$ar[$k] = iconv("UCS-2","UTF-8",pack("H4",substr($v,3,-1)));
elseif(substr($v,0,2) == "&#") {
//echo substr($v,2,-1)."\n";
$ar[$k] = iconv("UCS-2","UTF-8",pack("n",substr($v,2,-1)));
}
}
return join("",$ar);
}die( unescape('%u9996%u9875') );
手册的iconv部分不是有的吗function unescape($str) {
$str = rawurldecode($str);
preg_match_all("/(?:%u.{4})|&#x.{4};|&#\d+;|.+/U",$str,$r);
$ar = $r[0];
//print_r($ar);
foreach($ar as $k=>$v) {
if(substr($v,0,2) == "%u")
$ar[$k] = iconv("UCS-2","UTF-8",pack("H4",substr($v,-4)));
elseif(substr($v,0,3) == "&#x")
$ar[$k] = iconv("UCS-2","UTF-8",pack("H4",substr($v,3,-1)));
elseif(substr($v,0,2) == "&#") {
//echo substr($v,2,-1)."\n";
$ar[$k] = iconv("UCS-2","UTF-8",pack("n",substr($v,2,-1)));
}
}
return join("",$ar);
}die( unescape('%u9996%u9875') );
应该是取得它的unicode值
然后chr($val).chr($val)或者使用unpack,很好很强大的函数