关于读取.txt文件中的数据

Question

  $resourse= fopen ('record.txt','r');
                while ($content=fgets($resourse))
                {                    
                            list($date,$ip,$file_path,$goods,$price,$emsprice,$deliveryprice)=explode('|',$content);  
    $arr[] = $file_path;
                }?

Answer 1

地址是指images/upload/public/con_touroku.gif？<?php
$resourse= fopen ('record.txt','r');
$array = array();
while ($content=fgets($resourse))
{                    
    list($date,$ip,$file_path,$goods,$price,$emsprice,$deliveryprice)=explode('|',$content);    
array_push($array, $file_path);
}
echo var_dump($array);
echo $array[0];
?>

Answer 2

这样的话，echo $array[3];出现的结果是images/upload/public/con_touroku.gif
          echo $array[2];出现的结果是images/upload/public/back.bmpimages/upload/public/back.bmp
          echo $array[1];出现的结果是images/upload/public/bg_pic_3_1.gifimages/upload/public/bg_pic_3_1.gifimages/upload/public/bg_pic_3_1.gif

Answer 3

我PHP5.1下测试是正常的，你的版本是多少?

Answer 4

$str = '2008-03-19 17:55:03 ¦127.0.0.1 ¦images/upload/public/con_touroku.gif ¦goods3 ¦1000 ¦20 ¦10! 
2008-03-19 17:55:18 ¦127.0.0.1 ¦images/upload/public/bg_pic_3_1.gif ¦goods4 ¦1000 ¦15 ¦5! 
2008-03-19 17:55:27 ¦127.0.0.1 ¦images/upload/public/back.bmp ¦goods4 ¦1000 ¦15 ¦5! 
2008-03-19 17:55:32 ¦127.0.0.1 ¦images/upload/public/con_touroku.gif ¦goods4 ¦1000 ¦15 ¦5! ';
preg_match_all('/1 ¦(.*?) ¦/is', $str, $m);
print_r($m[1]);