想实现注册后才能登陆
<?php
$con = mysql_connect("localhost","root","");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}$u=$_POST['UN'];
$p=$_POST['PSD'];
$result = mysql_query("SELECT UserName, password FROM person WHERE UserName='$u'and password='$p'");
if($result=="TRUE") echo "<script language=javascript>
alert('登陆成功');
history.back();</script>";
else echo "<script language=javascript>
alert('请填写正确的用户名和密码');
history.back();
</script>";
?>
前台登陆界面:
<table width=215 border="0">
<tr>
<td> <form name="formName" action="denglu.php" onsubmit="return checkData()" method=post>
<h5>用户登录:</h5>
<label>用户名: <input type="text" name="UN" size="11"/></label><br />
<label>密 码: <input type ="password" name="PSD" size="10" /></label><br /><br /><a href="#">忘记密码</a><br />
<input type="submit" name="submit" value="登陆" / ></form> </td></tr>
<tr><td align="middle"><form action="other/会员注册条款.htm">
<input name="submit" type="submit" value="注册" />
</form></td></tr>
</table>
为什么用户名和密码正确了也一直显示“请填写正确的用户名和密码”啊??
我是新手~~求助啊~~
<?php
$con = mysql_connect("localhost","root","");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}$u=$_POST['UN'];
$p=$_POST['PSD'];
$result = mysql_query("SELECT UserName, password FROM person WHERE UserName='$u'and password='$p'");
if($result=="TRUE") echo "<script language=javascript>
alert('登陆成功');
history.back();</script>";
else echo "<script language=javascript>
alert('请填写正确的用户名和密码');
history.back();
</script>";
?>
前台登陆界面:
<table width=215 border="0">
<tr>
<td> <form name="formName" action="denglu.php" onsubmit="return checkData()" method=post>
<h5>用户登录:</h5>
<label>用户名: <input type="text" name="UN" size="11"/></label><br />
<label>密 码: <input type ="password" name="PSD" size="10" /></label><br /><br /><a href="#">忘记密码</a><br />
<input type="submit" name="submit" value="登陆" / ></form> </td></tr>
<tr><td align="middle"><form action="other/会员注册条款.htm">
<input name="submit" type="submit" value="注册" />
</form></td></tr>
</table>
为什么用户名和密码正确了也一直显示“请填写正确的用户名和密码”啊??
我是新手~~求助啊~~
//判断输入的用户名、密码是否正确
if (mysql_num_rows($result) > 0) {
echo "<script language=javascript>
alert('登陆成功');
history.back();</script>";
}
else {}
//你的if else控制结构中进行条件判断后显然要执行的是一个代码块,而不是判断后只执行一条语句
//所以 if {} else {} 花括号不能省略
denglu.php 中if($_POST['submit'])
{
$u=$_POST['UN'];
$p=$_POST['PSD'];
<form name="formName" action="denglu.php" method="post"> 去掉onsubmit,你用不到它....
....
全部
}
alert('登陆成功');
history.back();</script>";
else echo "<script language=javascript>
alert('请填写正确的用户名和密码');
history.back();
</script>";应写成
if($result=="TRUE"){ echo "<script language=javascript>
alert('登陆成功');
history.back();</script>";
}else{ echo "<script language=javascript>
alert('请填写正确的用户名和密码');
history.back();
</script>";
}
2 然后验证是否在数据库中(判断是否注册过)
3 接着核对帐号密码是否正确(跟2后面判断即可)
4 写session
5 进入系统给我点分吧,我穷
$res1=mysql_fetch_array($res);
if($username==$res1['username']&&$passwd=$res1['passwd']){}
这样 应该可以了