php如何获取节点属性的值

Question

例如
<?xml version='1.0' encoding="UTF-8"?>
<orguserlist>
<orguser  useraccount="[email protected]" manageright="USER">
<departmentid>/00/1</departmentid>
</orguser>
<orguser  useraccount="[email protected]" manageright="USER">
<departmentid>/00/1</departmentid>
</orguser>
<orguser  useraccount="[email protected]" manageright="USER">
<departmentid>/00/1</departmentid>
</orguser>
 </orguserlist>怎么取得useraccount ， manageright的值

Answer 1

$xml = <<< XML
<?xml version='1.0' encoding="UTF-8"?> 
<orguserlist> 
<orguser  useraccount="[email protected]" manageright="USER"> 
<departmentid>/00/1 </departmentid> 
</orguser> 
<orguser  useraccount="[email protected]" manageright="USER"> 
<departmentid>/00/1 </departmentid> 
</orguser> 
<orguser  useraccount="[email protected]" manageright="USER"> 
<departmentid>/00/1 </departmentid> 
</orguser> 
</orguserlist>
XML;$dom = simplexml_load_string($xml);
print_r($dom);
SimpleXMLElement Object
(
    [orguser] => Array
        (
            [0] => SimpleXMLElement Object
                (
                    [@attributes] => Array
                        (
                            [useraccount] => [email protected]
                            [manageright] => USER
                        )                    [departmentid] => /00/1 
                )            [1] => SimpleXMLElement Object
                (
                    [@attributes] => Array
                        (
                            [useraccount] => [email protected]
                            [manageright] => USER
                        )                    [departmentid] => /00/1 
                )            [2] => SimpleXMLElement Object
                (
                    [@attributes] => Array
                        (
                            [useraccount] => [email protected]
                            [manageright] => USER
                        )                    [departmentid] => /00/1 
                )        ))

Answer 2

<?php $doc = new DOMDocument(); $doc->load('xmlfile.xml');
 
 $node_lists = $doc->getElementsByTagName('orguser'); foreach ($node_lists as $node) {
   
 $useraccount  = $node->getAttribute('useraccount');
 $manageright  = $node->getAttribute('manageright'); echo '<li>useraccount : ' ,  $useraccount;
 echo '<li>manageright : ' ,  $manageright;  }
?> 

Answer 3

自己到网上找个这个可以实现：  
$simple ="conf/orguserlist.xml";
    $p = xml_parser_create();
    $filehandler = fopen($simple, "r");//打开文件
   while ($data = fread($filehandler, 409600)) 
   { 
      xml_parse_into_struct($p, $data, $vals, $index);
   } 
   fclose($filehandler); 
   xml_parser_free($p);
   foreach ($index['ORGUSER'] as $key)
   {
           $user_account=$vals[$key]['attributes']['USERACCOUNT'];

   }