有三个数组
$arr = array('张三','李四','王五');
$arr2 = array(100,200,300);
$arr3 = array(50,60,70);
如何平凑成另外一个数组$array,最后echo json_encode($array)输出如下格式
{"total":"3",
"result":[
{"date":"1","name":"张三","value":"100","other":"50"},
{"date":"1","name":"李四","value":"200","other":"60"},
{"date":"1","name":"王五","value":"300","other":"70"}
]
}
兄弟们,Help…
$arr = array('张三','李四','王五');
$arr2 = array(100,200,300);
$arr3 = array(50,60,70);
如何平凑成另外一个数组$array,最后echo json_encode($array)输出如下格式
{"total":"3",
"result":[
{"date":"1","name":"张三","value":"100","other":"50"},
{"date":"1","name":"李四","value":"200","other":"60"},
{"date":"1","name":"王五","value":"300","other":"70"}
]
}
兄弟们,Help…
解决方案 »
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$arr = array('张三','李四','王五');
$arr2 = array(100,200,300);
$arr3 = array(50,60,70);
$date=time();
$result['total']=sizeof($arr);
for($i=0;$i<sizeof($arr);$i++)
{
$result['result'][]=array("date"=>$date,"name"=>$arr[$i],"value"=>$arr2[$i],"other"=>$arr3[$i]);
}
echo json_encode($result);
/*
{"total":"3",
"result":[
{"date":"1","name":"张三","value":"100","other":"50"},
{"date":"1","name":"李四","value":"200","other":"60"},
{"date":"1","name":"王五","value":"300","other":"70"}
]
}
*/?>