Dim sta As String Dim receved() As Byte Dim inbutter As Variant Dim i As Integer Private Sub Command1_Click() Timer1.Enabled = Not Timer1.Enabled ''''''''''''''''''''''''''''''''''''''''''''''''''''MSComm1.InBufferCount = 0 '"清除发送缓冲区数据 ''''''''''''''''''''''''''''''''''''''''''''''''''' MSComm1.OutBufferCount = 0 '"清除接收缓冲区数据
Print "we" Print Tab Print "2343432424"
End SubPrivate Sub Form_Load()
With MSComm1 .CommPort = 3 .Settings = "1200,e,8,1" .RThreshold = 1 .InputMode = comInputModeBinary .PortOpen = True End With End Sub Private Sub MSComm1_OnComm()
Select Case MSComm1.CommEvent Case 2 MSComm1.InputLen = 0 inbutter = MSComm1.Input receved() = inbutter For i = 0 To UBound(receved) If Len(Hex(receved(i))) = 1 Then sta = sta & "0" & Hex(receved(i)) & " " Else sta = sta & Hex(receved(i)) & " " End If Next i End Select End SubPrivate Sub Timer1_Timer()
If Mid(sta, 1, 2) = "68" Then ''''''''''''''''''''''''''''''''''''''''''''''''''''''''''And Mid(sta, 40, 2) = "16" Then Label1.Caption = "88888"
Text1.Text = sta & vbCr Else Label1.Caption = "meiyou " & vbCrLf & "oihfoihf" End If
End Sub大家看看我的程序,sta是收的68然后再接受00等字符,我是想实现68 00 00 00 68 81 20 46 16这样的一串字符以后再换行!
怎么把我上面的这一组整合成一组?请参阅:http://www.vbgood.com/thread-83700-1-1.html
符串如何在text中实现强制换行?请设置文本框属性MultiLine为True就可.
http://download.csdn.net/source/1498644
Dim receved() As Byte
Dim inbutter As Variant
Dim i As Integer
Private Sub Command1_Click()
Timer1.Enabled = Not Timer1.Enabled
''''''''''''''''''''''''''''''''''''''''''''''''''''MSComm1.InBufferCount = 0 '"清除发送缓冲区数据
''''''''''''''''''''''''''''''''''''''''''''''''''' MSComm1.OutBufferCount = 0 '"清除接收缓冲区数据
Print "we"
Print Tab
Print "2343432424"
End SubPrivate Sub Form_Load()
With MSComm1
.CommPort = 3
.Settings = "1200,e,8,1"
.RThreshold = 1
.InputMode = comInputModeBinary
.PortOpen = True
End With
End Sub
Private Sub MSComm1_OnComm()
Select Case MSComm1.CommEvent
Case 2
MSComm1.InputLen = 0
inbutter = MSComm1.Input
receved() = inbutter
For i = 0 To UBound(receved)
If Len(Hex(receved(i))) = 1 Then
sta = sta & "0" & Hex(receved(i)) & " "
Else
sta = sta & Hex(receved(i)) & " "
End If
Next i
End Select
End SubPrivate Sub Timer1_Timer()
If Mid(sta, 1, 2) = "68" Then ''''''''''''''''''''''''''''''''''''''''''''''''''''''''''And Mid(sta, 40, 2) = "16" Then
Label1.Caption = "88888"
Text1.Text = sta & vbCr
Else
Label1.Caption = "meiyou " & vbCrLf & "oihfoihf"
End If
End Sub大家看看我的程序,sta是收的68然后再接受00等字符,我是想实现68 00 00 00 68 81 20 46 16这样的一串字符以后再换行!