各位大哥大姐帮帮忙,小妹vb制动点基础,能详细解答以下问题吗,谢谢了
一分钟接收一次数据存在access中并显示成曲线,应该怎么做?
坐标系原点定位于左下角picturebox的scale(0,y)-(x,0)中x,y应该怎么选择使所画曲线正确显示在picture中?
在网上搜索好多,但看不明白,直白一点picturemodestyle在画图有什么作用?
用mshflex显示access的数据,每次都会把所有记录都显示出来,我只想显示每次运行程序时的记录,应该怎么做?
一分钟接收一次数据存在access中并显示成曲线,应该怎么做?
坐标系原点定位于左下角picturebox的scale(0,y)-(x,0)中x,y应该怎么选择使所画曲线正确显示在picture中?
在网上搜索好多,但看不明白,直白一点picturemodestyle在画图有什么作用?
用mshflex显示access的数据,每次都会把所有记录都显示出来,我只想显示每次运行程序时的记录,应该怎么做?
2、用MSChart控件绘制曲线。
3、具体代码如下:
Option Explicit
'对于二维散点图来说,第一列代表了X轴坐标,第二列代表了Y轴坐标
'因此在定义二维数据时,第二维定义为0到1,第一维代表了第几点数据,可根据数据点数变化
'下面以数据点数有21点为列子
Dim MyData(360, 1) As Variant
Dim DataT(360, 1) As Variant
Private Const PI = 3.1415926
Dim intC As Integer
Dim dblStep As DoublePrivate Sub Command1_Click()
Timer1.Enabled = Not Timer1.Enabled
If Timer1.Enabled Then Command1.Caption = "停止示波器"
If Not Timer1.Enabled Then Command1.Caption = "启动示波器"
End SubPrivate Sub Form_Load()
Dim I As Integer
dblStep = 8 * PI / 360
'-----x轴坐标值-----Y轴坐标值----------
For I = 0 To 360
MyData(I, 0) = I
MyData(I, 1) = 149 * Sin(dblStep * I) + 150
Next I
For I = 0 To 360
DataT(I, 0) = I
DataT(I, 1) = 149 * Cos(dblStep * I) + 150
Next I
intC = 1
'波形图外观设置
With MSChart1
.TitleText = "速度 m/min"
' '设置图线的外观
.Plot.SeriesCollection(1).Pen.Width = 40
.Plot.SeriesCollection(1).Pen.Style = VtPenStyleSolid
' '设置XY轴
.Plot.Axis(VtChAxisIdX).ValueScale.Auto = False
.Plot.Axis(VtChAxisIdY).ValueScale.Auto = False
'// 设置最大值
.Plot.Axis(VtChAxisIdX).ValueScale.Maximum = 360
.Plot.Axis(VtChAxisIdY).ValueScale.Maximum = 300
'// 设置最小值
.Plot.Axis(VtChAxisIdY).ValueScale.Minimum = 0
.Plot.Axis(VtChAxisIdX).ValueScale.Minimum = 0
'//
.Plot.Axis(VtChAxisIdX).ValueScale.MajorDivision = 6 'X轴主要网格数量
.Plot.Axis(VtChAxisIdY).ValueScale.MajorDivision = 6 'Y轴主要网格数量
.Plot.Axis(VtChAxisIdX).ValueScale.MinorDivision = 0 'X轴次要网格数量
.Plot.Axis(VtChAxisIdY).ValueScale.MinorDivision = 0 'Y轴次要网格数量
' .Plot.Axis(VtChAxisIdX).AxisGrid.MajorPen.Style = VtPenStyleDotted
' .Plot.Axis(VtChAxisIdY).AxisGrid.MajorPen.Style = VtPenStyleDotted
MSChart1.Plot.AutoLayout = False
MSChart1.Plot.UniformAxis = False
MSChart1.chartType = VtChChartType2dXY '设置图形为二维散点图
MSChart1.ChartData = MyData '数据
End With
End SubPrivate Sub Timer1_Timer()
Dim intP As Integer
For intP = 0 To 359
MyData(intP, 1) = MyData(intP + 1, 1)
Next intP
MyData(360, 1) = 149 * Sin(intC * dblStep) + 150
intC = (intC + 1) Mod 360
MSChart1.ChartData = MyData
End Sub这个只是模拟的而已,仅供借鉴
如果用picturebox应该怎么做?scale(0,picture1.height)-(picturebox1.width,0)为什么曲线没显示在picturebox中?
关于图片绘图问题,要用Line方法。
'添加 Command1 Picture1
Dim i%, jj%, a(31) As Integer
Dim x1%, y1%, x2%, y2%, oldx1%, oldy1%, perpixw!, perpixh!, perdivx!, perdivy!
Private Sub Form_Load()
Picture1.AutoSize = True
Picture1.AutoRedraw = True
Me.AutoRedraw = True
End Sub
Private Sub Command1_Click()
For i = 1 To 31
jj = Int(Rnd * 1000)
a(i) = jj
Next i
drawpic
End Sub
Private Sub drawpic()
On Error Resume Next
perpixw = (Picture1.Width) / 12
perpixh = Picture1.Height / 10
oldx1 = 0
oldy1 = Picture1.Height
Call drawline
x1 = Picture1.Left - 500
y1 = Picture1.Top - 100
For i = 1000 To 0 Step -50 ‘为什么step -50,如果把1000换成变化的值,step该怎么设置
Me.CurrentX = x1
Me.CurrentY = y1
y1 = y1 + Int(Picture1.Height / 20) ’
If i Mod 100 = 0 Then Me.Print Str(i)
Next i
For i = 1 To 31 ’想让纵坐标显示时间量程分别为3,6,12,24,该怎么处理
x1 = (i - 1) * perpixw
y1 = a(i) * perpixh
Me.CurrentY = Picture1.Top + Picture1.Height + 100
Me.CurrentX = (Picture1.Left - 100) + x1
If i Mod 5 = 0 Then Print Format(Str(i), "00")
Picture1.Line (oldx1, oldy1)-(x1, y1), vbRed ‘不懂什么意思,如果去掉就不会有曲线
oldx1 = x1: oldy1 = y1
Next i
End Sub
Private Sub drawline()
Picture1.Cls
Me.Cls
Me.FontSize = 10
Me.ForeColor = QBColor(0)
perdivx = Picture1.Width \ 12
perdivy = Picture1.Height \ 10
x1 = 0: x2 = Picture1.Width
For yy = 0 To Picture1.Height Step perdivy
Picture1.Line (x1, yy)-(x2, yy), QBColor(3)
Next yy
y1 = 0: y2 = Picture1.Height
For x1 = 0 To Picture1.Width Step perdivx
Picture1.Line (x1, y1)-(x1, y2), QBColor(3)
Next x1
End Sub
上面源码为什么没有定义scale呢?,敬请指教,谢谢
这个你可以自己定,比如将1000换成100,再用-50 ,那么就只能花3个刻度(100、50、0)
,但如果用-5,就不一样了,就能画21个刻度了(100/5+1)For i = 1 To 31 ’想让纵坐标显示时间量程分别为3,6,12,24,该怎么处理
你只需要在你想绘线的地方绘制即可。
Picture1.Line (oldx1, oldy1)-(x1, y1), vbRed ‘不懂什么意思,如果去掉就不会有曲线
这句就是绘制曲线的语句,每次绘制一小段线段,多条首尾相连的线段连接起来就成了曲线了。