输出数组的代码(不一定对,仅供参考) Private Sub Form_Load() Form1.Show Arr = Array(Array(1, 2, 3, 4, 5, 6), Array(2, 3, 4, 5, 6, 7), Array(3, 4, 5, 6, 7, 8)) 'MsgBox UBound(Arr, 2)For i = 0 To UBound(Arr, 1) s = "" For j = 0 To UBound(Arr(0), 1) s = s & Arr(i)(j) & " " Next Print s Next For j = 0 To UBound(Arr(0), 1) s = "" For i = 0 To UBound(Arr, 1) s = s & Arr(i)(j) & " " Next Print s Next End Sub
Dim Arr, i As Integer, j As Integer Dim s As String Arr = Array(Array(1, 2, 3, 4, 5, 6), Array(2, 3, 4, 5, 6, 7), Array(3, 4, 5, 6, 7, 8)) For i = 0 To UBound(Arr) s = "" For j = 0 To UBound(Arr(i)) s = s & Arr(i)(j) & " " Next Debug.Print s Next 老张的代码很正确!至于转置矩阵,因为,用Arr = Array(Array(1, 2, 3, 4, 5, 6), Array(2, 3, 4, 5, 6, 7), Array(3, 4, 5, 6, 7, 8))生成的数组不一定是矩阵,如:Arr = Array(Array(1), Array(2, 3), Array(3, 4, 8)) 这样也行,所以,表示矩阵最好用二维数组
Private Sub Form_Load()
Form1.Show
Arr = Array(Array(1, 2, 3, 4, 5, 6), Array(2, 3, 4, 5, 6, 7), Array(3, 4, 5, 6, 7, 8))
'MsgBox UBound(Arr, 2)For i = 0 To UBound(Arr, 1)
s = ""
For j = 0 To UBound(Arr(0), 1)
s = s & Arr(i)(j) & " "
Next
Print s
Next
For j = 0 To UBound(Arr(0), 1)
s = ""
For i = 0 To UBound(Arr, 1)
s = s & Arr(i)(j) & " "
Next
Print s
Next
End Sub
Dim s As String
Arr = Array(Array(1, 2, 3, 4, 5, 6), Array(2, 3, 4, 5, 6, 7), Array(3, 4, 5, 6, 7, 8)) For i = 0 To UBound(Arr)
s = "" For j = 0 To UBound(Arr(i))
s = s & Arr(i)(j) & " "
Next Debug.Print s
Next
老张的代码很正确!至于转置矩阵,因为,用Arr = Array(Array(1, 2, 3, 4, 5, 6), Array(2, 3, 4, 5, 6, 7), Array(3, 4, 5, 6, 7, 8))生成的数组不一定是矩阵,如:Arr = Array(Array(1), Array(2, 3), Array(3, 4, 8))
这样也行,所以,表示矩阵最好用二维数组