Private Sub Combo1_KeyDown(Index As Integer, KeyCode As Integer, Shift As Integer)
MsgBox KeyCode
If KeyCode = 38 Then aaaagq_ReCall
If KeyCode = 40 Then SendKeys "{TAB}"
End Sub没有获得上下,请问如何解决?谢谢大家
form.keypreview 设置为true
MsgBox KeyCode
If KeyCode = 38 Then aaaagq_ReCall
If KeyCode = 40 Then SendKeys "{TAB}"
End Sub没有获得上下,请问如何解决?谢谢大家
form.keypreview 设置为true
MsgBox KeyCode
If KeyCode = 38 Then MsgBox "上"
If KeyCode = 40 Then MsgBox "下"
End Sub在我的机器上很好啊,捕捉到了
Private Sub Combo1_KeyDown(Index As Integer, KeyCode As Integer, Shift As Integer)
If KeyCode = 38 Then MsgBox "上"
If KeyCode = 40 Then MsgBox "下"
End Sub
Combo1(0).Locked = True 如果是false就没问题了。但是这里的true是我必须的,这个问题该如何解决阿?谢谢大家。
Private Sub Combo1_KeyDown(KeyCode As Integer, Shift As Integer)
Combo1.Locked = False
End Sub
Private Sub Combo1_KeyUp(KeyCode As Integer, Shift As Integer)
If KeyCode = 38 Then MsgBox "上"
If KeyCode = 40 Then MsgBox "下"
Combo1.Locked = True
End Sub