Private Sub Combo1_Change()
End Sub
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Private Sub Combo2_Change()
End Sub
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Private Sub Combo3_Change()
End Sub
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Private Sub Form_Load()
combo1.additem " 2 " , 1
combo1.additem " 3 " , 2
combo2.visible = false
combo3.visible = false
end sub提问:当combo1.text = 1的时候,如何让combo2.visible = true
当combo1.text = 2的时候,如何让combo3.visible = true
要求代码
End Sub
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Private Sub Combo2_Change()
End Sub
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Private Sub Combo3_Change()
End Sub
————————————————————————
Private Sub Form_Load()
combo1.additem " 2 " , 1
combo1.additem " 3 " , 2
combo2.visible = false
combo3.visible = false
end sub提问:当combo1.text = 1的时候,如何让combo2.visible = true
当combo1.text = 2的时候,如何让combo3.visible = true
要求代码
Private Sub Combo1_Click()
Select Case Combo1.ListIndex Case 0 Combo2.Visible = Not Combo2.Visible Case 1 Combo3.Visible = Not Combo2.Visible Case 3 End SelectEnd SubPrivate Sub Form_Load()
Combo1.AddItem "1"
Combo1.AddItem "3"
Combo1.AddItem "2"
Combo1.AddItem "3"
Combo2.Visible = False
Combo3.Visible = False
End Sub
if Combo1.text = "1" then
Combo2.Visible = True
else
Combo3.Visible = True
end if
End Sub
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Private Sub Combo2_Change()
End Sub
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Private Sub Combo3_Change()
End Sub
————————————————————————
Private Sub Form_Load()
combo1.additem "1" , 1
combo1.additem "2" , 2
combo2.visible = false
combo3.visible = false
end sub
正确
你在additem的时候 " 2 " 两边有空格,如果不去掉,判断的时候也要加上。也可以判断ListIndex
combo1.additem " 2 " , 1'指定了ID
combo1.additem " 3 " , 2
combo2.visible = false
combo3.visible = false
end sub提问:当combo1.text = 1----------------按题意应该是ID为1 时 因为你 文本里你的list列表里并没有1
的时候,如何让combo2.visible = true
当combo1.text = 2的时候,如何让combo3.visible = true
要求代码
列表里没有1,可是他可以在运行时手动输入1阿