FileNum = FreeFile()
strFileName = "D:\tool\VB98\myapp\ATPv1.01\v4.2\RoadNode202Left.txt"
Open strFileName For Input As #FileNum
For i = 0 To 468
Road202NodeLeft(i) =Line Input #FileNum,(Chr(13) + Chr(10))'(*)
Debug.Print Road202NodeLeft(i)
Next i
Close
老是:Compile error
Expected:end of statement
msdn上说:Input # 语句期待一个变量作为其第二个参数。
但是line input的语法说:Line Input # 语句一次只从文件中读出一个字符,直到遇到回车符 (Chr(13)) 或回车–换行符 (Chr(13) + Chr(10)) 为止。回车–换行符将被跳过,而不会被附加到字符串上。
我该怎么写(*)句了?!
strFileName = "D:\tool\VB98\myapp\ATPv1.01\v4.2\RoadNode202Left.txt"
Open strFileName For Input As #FileNum
For i = 0 To 468
Road202NodeLeft(i) =Line Input #FileNum,(Chr(13) + Chr(10))'(*)
Debug.Print Road202NodeLeft(i)
Next i
Close
老是:Compile error
Expected:end of statement
msdn上说:Input # 语句期待一个变量作为其第二个参数。
但是line input的语法说:Line Input # 语句一次只从文件中读出一个字符,直到遇到回车符 (Chr(13)) 或回车–换行符 (Chr(13) + Chr(10)) 为止。回车–换行符将被跳过,而不会被附加到字符串上。
我该怎么写(*)句了?!
你该这么写的~
Line Input #FileNum, [设置一个字string变量,用于装载读入的字串]
dim strtmp as string
open .......... as #filenum
Do While Not EOF(FileNum)
line input #filenum,strtmp
text1.text = text1.text & strtmp & vbcrlf '注意,textbox的"允许换行"属性为真
Loop
但是我的文本里面的值是doule数值,如果我用string把doule值提出来,该怎么还原并写入数组了?!
dim Road202NodeLeft(468) as double
Open strFileName For Input As #FileNum
input #FileNum,468
for i=1 to 468
input #FileNum,Road202NodeLeft(i)
next i
strFileName = "D:\tool\VB98\myapp\ATPv1.01\v4.2\RoadNode202Left.txt"
Open strFileName For Input As #1
For i = 0 To 468
Input #1, Road202NodeLeft(468)
Next i