各位大侠请帮我说明一哈,下面这几句的功能得要是得到一个什么结果~~~最好能举例说明~ U_now = dateadd("h",U_TZone-CFG_ZoneServer,now())
dim day_(3),day_a(3)
day_a(0)=datevalue(U_now)
day_a(1)=dateadd("d",-1,day_a(0))
day_a(2)=cdate(year(day_a(0)) & "-" & month(day_a(0)) & "-1")
day_a(3)=cdate(year(day_a(0)) & "-1-1")
dim day_(3),day_a(3)
day_a(0)=datevalue(U_now)
day_a(1)=dateadd("d",-1,day_a(0))
day_a(2)=cdate(year(day_a(0)) & "-" & month(day_a(0)) & "-1")
day_a(3)=cdate(year(day_a(0)) & "-1-1")
Private Sub Command1_Click()
U_TZone_CFG_ZoneServer = 2
U_now = DateAdd("h", U_TZone - CFG_ZoneServer, Now())
Dim day_(3), day_a(3)
day_a(0) = DateValue(U_now)
day_a(1) = DateAdd("d", -1, day_a(0))
day_a(2) = CDate(Year(day_a(0)) & "-" & Month(day_a(0)) & "-1")
day_a(3) = CDate(Year(day_a(0)) & "-1-1")
For Each a In day_a
Debug.Print a
Next
End Sub
5. 同上
dim day_(3),day_a(3)
day_a(0)=datevalue(U_now)
day_a(1)=dateadd("d",-1,day_a(0))
day_a(2)=cdate(year(day_a(0)) & "-" & month(day_a(0)) & "-1")
day_a(3)=cdate(year(day_a(0)) & "-1-1")假如 U_TZone-CFG_ZoneServer = 8
U_now = 2004-12-10 19:45:20
day_a(0) = 2004-12-10 19:45:20
day_a(1) = 2004-12-09 19:45:20
day_a(2) = 2004-12-01 00:00:00
day_a(3) = 2004-01-01 00:00:00