假设文本内容格式为
12 22 23 23 34
13 34 34 34 34
则LISTVIEW控件显示为
XXX XXX XXX XXX XXX
12 22 23 23 34
13 34 34 34 34
XXX分别为控件的5个column headers
帮我把程序改下,谢谢
Private Sub Form_Load()
Dim tpStr As String, i As Integer
fileName = App.Path & "\test.txt"
If Dir(fileName) <> "" Then
'加载数据
Open fileName For Input As #1
Do While Not EOF(1)
With ListView1.ListItems.Add()
For i = 0 To 4
Line Input #1, tpStr
If i = 0 Then
.Text = tpStr
Else
.SubItems(i) = tpStr
End If
Next i
End With
Loop
Close #1
End If
End Sub
12 22 23 23 34
13 34 34 34 34
则LISTVIEW控件显示为
XXX XXX XXX XXX XXX
12 22 23 23 34
13 34 34 34 34
XXX分别为控件的5个column headers
帮我把程序改下,谢谢
Private Sub Form_Load()
Dim tpStr As String, i As Integer
fileName = App.Path & "\test.txt"
If Dir(fileName) <> "" Then
'加载数据
Open fileName For Input As #1
Do While Not EOF(1)
With ListView1.ListItems.Add()
For i = 0 To 4
Line Input #1, tpStr
If i = 0 Then
.Text = tpStr
Else
.SubItems(i) = tpStr
End If
Next i
End With
Loop
Close #1
End If
End Sub
dim tplist(4)Do While Not EOF(1)
line input #1,tpstr
tplist=split (tpstr," ") '不晓得你的空格数量固定不。或者用别的符号。
With ListView1.ListItems.Add()
For i = 0 To 4
If i = 0 Then
.Text = tpStr
Else
.SubItems(i) = tpStr
End If
Next i
End With
Loop
这个是没偷懒的。:)
另外你的listview需要有5列。少了就出错。Private Sub Form_Load()
Dim tpStr As String, i As Integer
FileName$ = App.Path & "\test.txt"
If Dir(FileName) <> "" Then
Open FileName For Input As #1
Do While Not EOF(1)
Line Input #1, tpStr
ReDim tplist(4) As String
tplist = Split(tpStr, " ") '不晓得你的空格数量固定不。或者用别的符号。
With ListView1.ListItems.Add()
For i = 0 To 4
If i = 0 Then
.Text = tplist(0)
Else
.SubItems(i) = tplist(i)
End If
Next i
End With
Loop
Close #1
End If
End Sub