请问各路高手,有这样一道提,该如何做?
aX^2+bX+c=0
当a>0 b^2+4ac>0
b^2+4ac=0
b^2+4ac<0
当a=0 b^2+4ac>0
b^2+4ac=0
b^2+4ac<0
当a<0 b^2+4ac>0
b^2+4ac=0
b^2+4ac<0
时求出X的值
我要原程序,最好加上讲解,谢谢!
E-mail:[email protected]
aX^2+bX+c=0
当a>0 b^2+4ac>0
b^2+4ac=0
b^2+4ac<0
当a=0 b^2+4ac>0
b^2+4ac=0
b^2+4ac<0
当a<0 b^2+4ac>0
b^2+4ac=0
b^2+4ac<0
时求出X的值
我要原程序,最好加上讲解,谢谢!
E-mail:[email protected]
if a>0 or a<0 then
ls=sqr(b*b-4ac)
if ls>=0 then
x1=(-b+ls)/(2*a)
x2=(-b+ls)/(2*a)
else
msgbox "error"
end if
else
x1=x2=-c/b
end ifнезнаю
Dim a As Single
Dim b As Single
Dim c As Single
Dim x1 As Single
Dim x2 As Single
Dim t As Single
Dim y As Single
a = Int(InputBox(输入a的值))
b = Int(InputBox(输入b的值))
c = Int(InputBox(输入c的值))
t = b ^ 2 + 4 * a * c
y = b ^ 2 - 4 * a * c
If a = 0 Then
If t = 0 And c = 0 Then x1 = 0: x2 = x1: Print x1
If t = 0 And c <> 0 Then Print "无解"
If t <> 0 Then
If b <> 0 Then x1 = -c / b: x2 = x1: Print x1
End If
End If
If a > 0 Or a < 0 Then
If y = 0 Then x1 = (-1 * b) / (2 * a): x2 = x1: Print x1
If y > 0 Then x1 = (-1 * b + Sqr(y)) / (2 * a): x2 = (-1 * b - Sqr(y)) / (2 * a): Print x1, x2
If y < 0 Then
Print "x1="; -1 * b / (2 * a) & "+" & Sqr(-y) / (2 * a) & "i",
Print "x2="; -1 * b / (2 * a) & "-" & Sqr(-y) / (2 * a) & "i"
End If
End If
End Sub
Private Sub Command1_Click()
calu
End Sub
看不懂你那个a<>0时,判断b^2+4ac干吗用
这三句改称下面
a = CSng(InputBox(输入a的值))
b = CSng(InputBox(输入b的值))
c = CSng(InputBox(输入c的值))