for i=1 to 52
a1=a1+byarray1[i]
nextfor i=105 to 156
a2=a1+byarray2[i]
nexta3=a1+a2
a3就是两个数组你需要的那些元素组成的
不知道我的理解是否正确?!
a1=a1+byarray1[i]
nextfor i=105 to 156
a2=a1+byarray2[i]
nexta3=a1+a2
a3就是两个数组你需要的那些元素组成的
不知道我的理解是否正确?!
dim SubStr2 as string
For i = 1 To 52
SubStr1 = SubStr1 + Chr(bytArray1(i))
Next i
For i = 105 To 156
SubStr2 = SubStr2 + Chr(bytArray2(i))
Next i
然后比较SubStr1和SubStr2
dim j as integer
for i=1 to 52
if array1(i)<array(104+i) then
j=1
exit for
else if array1(i)<array(104+i) then
j=0
exit for
end if
next i
mid (array1,1,52)
mid (array2,105,52)