Open XX.txt For Input As #File1
Line Input #File1, strLine
strLine﹕返回string
Line Input #File1, strLine
strLine﹕返回string
解决方案 »
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http://www.csdn.net/expert/Topic/50/50275.shtm'写入
Dim cnn As New ADODB.Connection
Dim rec As New ADODB.Recordset
Dim FileNumber As Long
Const KB = 1024
Const n = 1
cnn.Open "Provider=Microsoft.Jet.OLEDB.3.51;Persist Security Info=False;Data Source=" & App.Path & "\mmxdb97.mdb"
rec.Open "bmp", cnn, adOpenKeyset, adLockOptimistic, adCmdTable
Debug.Print rec.Fields(1).Type
Dim FileBuffer() As Byte
rec.AddNew
FileNumber = FreeFile
'用 CommonDialog 选择文件
Open CommonDialog1.FileName For Binary Access Read As #FileNumber
Dim lSize As Long
lSize = FileLen(CommonDialog1.FileName)
ReDim FileBuffer(1 To n * KB)
Do While lSize >= (n * KB)
Get #FileNumber, , FileBuffer
rec.Fields.Item(1).AppendChunk FileBuffer
lSize = lSize - (n * KB)
Loop
If lSize > 0 Then
ReDim FileBuffer(1 To lSize) As Byte
Get #FileNumber, , FileBuffer
rec.Fields.Item(1).AppendChunk FileBuffer
End If
Close #FileNumber
rec.Update
l = filelen(sfile)dim lf as long
lf = freefile()
open sfile for binary as #lfdim bt() as byte
redim bt(l-1)get #lf,,bt
close #lfrs(0)=btrs.update
http://www.csdn.net/expert/Topic/50/50275.shtm