某文件,现在已经知道他的是这样加密实现的
00015584h: 2E B9 24 03 69 F3 A7 03 02 00 00 00 01 00 7A 10 ; .?.i螫.......z.
00015594h: 0A 00 0C 00 00 00 3C 39 42 00 00 00 00 00 00 00 ; ......<9B.......
000155a4h: 00 00 D3 CB 05 00 36 00 00 00 BC 81 76 00 00 00 ; ..铀..6...紒v...
000155b4h: 00 00 00 00 00 00 E3 EA DF 01 04 00 00 00 ; ......汴?....
000155c2h: 2F B9 24 03 69 F3 A7 03 02 00 00 00 01 00 7A 10 ; /?.i螫.......z.
000155d2h: 0A 00 0C 00 00 00 3C 39 42 00 00 00 00 00 00 00 ; ......<9B.......
000155e2h: 00 00 D3 CB 05 00 36 00 00 00 BC 81 76 00 00 00 ; ..铀..6...紒v...
000155f2h: 00 00 00 00 00 00 E3 EA DF 01 04 00 00 00 ; ......汴?....前四组16进制代码为物品代码 要倒着读,并转换成10进制转成了实物的代码
每组字符是62个字节,挨着的,
上面是两段代码,
2E B9 24 03 倒着读是 324B92E 转成十进制后是52738350 这个即是解密后的代码下一个
2fb92403>>324B92F>>52738351 后面的一些字节不知道什么意思不用管他,反正一段是62个字节想编程实现批量读取并转换成十进制,怎么才能实现呢,各位下面是复制的一部分代码:
00015584h: 2E B9 24 03 69 F3 A7 03 02 00 00 00 01 00 7A 10 ; .?.i螫.......z.
00015594h: 0A 00 0C 00 00 00 3C 39 42 00 00 00 00 00 00 00 ; ......<9B.......
000155a4h: 00 00 D3 CB 05 00 36 00 00 00 BC 81 76 00 00 00 ; ..铀..6...紒v...
000155b4h: 00 00 00 00 00 00 E3 EA DF 01 04 00 00 00 2F B9 ; ......汴?..../?
000155c4h: 24 03 69 F3 A7 03 02 00 00 00 01 00 7A 10 0A 00 ; $.i螫.......z...
000155d4h: 0C 00 00 00 3C 39 42 00 00 00 00 00 00 00 00 00 ; ....<9B.........
000155e4h: D3 CB 05 00 36 00 00 00 BC 81 76 00 00 00 00 00 ; 铀..6...紒v.....
000155f4h: 00 00 00 00 E3 EA DF 01 04 00 00 00 30 B9 24 03 ; ....汴?....0?.
00015604h: 69 F3 A7 03 02 00 00 00 01 00 7A 10 0A 00 0C 00 ; i螫.......z.....
00015614h: 00 00 3C 39 42 00 00 00 00 00 00 00 00 00 D3 CB ; ..<9B.........铀
00015624h: 05 00 36 00 00 00 BC 81 76 00 00 00 00 00 00 00 ; ..6...紒v.......
00015634h: 00 00 E3 EA DF 01 04 00 00 00 31 B9 24 03 69 F3 ; ..汴?....1?.i?
00015644h: A7 03 02 00 00 00 01 00 7A 10 0A 00 0C 00 00 00 ; ?......z.......
00015654h: 3C 39 42 00 00 00 00 00 00 00 00 00 D3 CB 05 00 ; <9B.........铀..
00015664h: 36 00 00 00 BC 81 76 00 00 00 00 00 00 00 00 00 ; 6...紒v.........
00015674h: E3 EA DF 01 04 00 00 00 32 B9 24 03 69 F3 A7 03 ; 汴?....2?.i螫.
00015684h: 02 00 00 00 01 00 7A 10 0A 00 0C 00 00 00 3C 39 ; ......z.......<9
00015694h: 42 00 00 00 00 00 00 00 00 00 D3 CB 05 00 36 00 ; B.........铀..6.
000156a4h: 00 00 BC 81 76 00 00 00 00 00 00 00 00 00 E3 EA ; ..紒v.........汴
000156b4h: DF 01 04 00 00 00 ; ?....
00015584h: 2E B9 24 03 69 F3 A7 03 02 00 00 00 01 00 7A 10 ; .?.i螫.......z.
00015594h: 0A 00 0C 00 00 00 3C 39 42 00 00 00 00 00 00 00 ; ......<9B.......
000155a4h: 00 00 D3 CB 05 00 36 00 00 00 BC 81 76 00 00 00 ; ..铀..6...紒v...
000155b4h: 00 00 00 00 00 00 E3 EA DF 01 04 00 00 00 ; ......汴?....
000155c2h: 2F B9 24 03 69 F3 A7 03 02 00 00 00 01 00 7A 10 ; /?.i螫.......z.
000155d2h: 0A 00 0C 00 00 00 3C 39 42 00 00 00 00 00 00 00 ; ......<9B.......
000155e2h: 00 00 D3 CB 05 00 36 00 00 00 BC 81 76 00 00 00 ; ..铀..6...紒v...
000155f2h: 00 00 00 00 00 00 E3 EA DF 01 04 00 00 00 ; ......汴?....前四组16进制代码为物品代码 要倒着读,并转换成10进制转成了实物的代码
每组字符是62个字节,挨着的,
上面是两段代码,
2E B9 24 03 倒着读是 324B92E 转成十进制后是52738350 这个即是解密后的代码下一个
2fb92403>>324B92F>>52738351 后面的一些字节不知道什么意思不用管他,反正一段是62个字节想编程实现批量读取并转换成十进制,怎么才能实现呢,各位下面是复制的一部分代码:
00015584h: 2E B9 24 03 69 F3 A7 03 02 00 00 00 01 00 7A 10 ; .?.i螫.......z.
00015594h: 0A 00 0C 00 00 00 3C 39 42 00 00 00 00 00 00 00 ; ......<9B.......
000155a4h: 00 00 D3 CB 05 00 36 00 00 00 BC 81 76 00 00 00 ; ..铀..6...紒v...
000155b4h: 00 00 00 00 00 00 E3 EA DF 01 04 00 00 00 2F B9 ; ......汴?..../?
000155c4h: 24 03 69 F3 A7 03 02 00 00 00 01 00 7A 10 0A 00 ; $.i螫.......z...
000155d4h: 0C 00 00 00 3C 39 42 00 00 00 00 00 00 00 00 00 ; ....<9B.........
000155e4h: D3 CB 05 00 36 00 00 00 BC 81 76 00 00 00 00 00 ; 铀..6...紒v.....
000155f4h: 00 00 00 00 E3 EA DF 01 04 00 00 00 30 B9 24 03 ; ....汴?....0?.
00015604h: 69 F3 A7 03 02 00 00 00 01 00 7A 10 0A 00 0C 00 ; i螫.......z.....
00015614h: 00 00 3C 39 42 00 00 00 00 00 00 00 00 00 D3 CB ; ..<9B.........铀
00015624h: 05 00 36 00 00 00 BC 81 76 00 00 00 00 00 00 00 ; ..6...紒v.......
00015634h: 00 00 E3 EA DF 01 04 00 00 00 31 B9 24 03 69 F3 ; ..汴?....1?.i?
00015644h: A7 03 02 00 00 00 01 00 7A 10 0A 00 0C 00 00 00 ; ?......z.......
00015654h: 3C 39 42 00 00 00 00 00 00 00 00 00 D3 CB 05 00 ; <9B.........铀..
00015664h: 36 00 00 00 BC 81 76 00 00 00 00 00 00 00 00 00 ; 6...紒v.........
00015674h: E3 EA DF 01 04 00 00 00 32 B9 24 03 69 F3 A7 03 ; 汴?....2?.i螫.
00015684h: 02 00 00 00 01 00 7A 10 0A 00 0C 00 00 00 3C 39 ; ......z.......<9
00015694h: 42 00 00 00 00 00 00 00 00 00 D3 CB 05 00 36 00 ; B.........铀..6.
000156a4h: 00 00 BC 81 76 00 00 00 00 00 00 00 00 00 E3 EA ; ..紒v.........汴
000156b4h: DF 01 04 00 00 00 ; ?....
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{
long code; //元素编码
char name[2];//元素名称
char xxx[58];//未知数据,占58字节
}ELEMENT;void main()
{
ELEMENT e[100];
FILE *fp;
long off=0x00; //数据开始位置
int i; fp=fopen("XXXXX.XXX","wb");
if(NULL==fp) return; fseek(fp,off,0);
memset(e,0,6200); fread(e,62,100,fp);
for(i=0;i<100;i++)
printf("第%3d个数据编码: %08x %d",i,e[i].code,e[i].code);
fclose(fp);
}楼主如果懂链表,把上面的结构定义改改,就可以动态一个一个读了
QQ7199963
xxx[58]应改为
char xxx[56];////未知数据,占56字节如果楼主研究到其他参数
把这56个字节分开来就搞定如果需要帮助,把操作这个的软件和数据文件发来这是个很简单的问题