内嵌汇编的问题

DWORD Code_ofs0,Code_ofs1,SizeLen; __asm
{
mov Code_ofs0,offset Get_Explorer_0
mov Code_ofs1,offset Get_Explorer_4
jmp Get_Explorer_4Get_Explorer_0:
call Get_Explorer_A
Get_Explorer_A: 
pop eax
mov ebx,offset Get_Explorer_4
sub ebx,offset Get_Explorer_A
add eax,ebx
push eax
call Get_Explorer_C
ret
Get_Explorer_C:
push    ebp
mov     ebp,esp
sub     esp,18h
push    ebx
push    esi
mov     esi,[ebp+8]
and     dword ptr [ebp-4],0
push    edi
mov     ecx,[esi+4]
mov     eax,[esi]
mov     [ebp-0Ch],ecx
mov     ecx,[esi+8]
mov     [ebp-10h],ecx
mov     ecx,[esi+0Ch]
mov     [ebp+8],ecx
mov     ecx,[esi+10h]
mov     [ebp-8],ecx
mov     ecx,[esi+14h]
lea     edi,[esi+18h]
mov     [ebp-18h],ecx
push    edi
call    eax
mov     ebx,eax
test    ebx,ebx
jz      loc_0040109B
mov     eax,[ebx+34h]
mov     [ebp-14h],eax
call    dword ptr [ebx+30h]
loc_00401045:
cmp     dword ptr [ebp-4],0
jnz     loc_00401061
cmp     byte ptr [esi+11Ch],0
lea     eax,[esi+11Ch]
jz      loc_00401061
push    eax
call    dword ptr [ebp+8]
mov     [ebp-4],eax
loc_00401061:
lea     eax,[esi+220h]
push    eax
push    0
push    1F0003h
call    dword ptr [ebp-0Ch]
test    eax,eax
jnz     loc_00401080
push    1F4h
call    dword ptr [ebp-8]
jmp     loc_00401045
loc_00401080:
push    eax
call    dword ptr [ebp-10h]
call    dword ptr [ebp-14h]
push    ebx
call    dword ptr [ebp-18h]
push    edi
call    dword ptr [ebp+8]
push    0C8h
call    dword ptr [ebp-8]
push    edi
call    dword ptr [ebp+8]
loc_0040109B:
pop     edi
pop     esi
pop     ebx
leave
ret     4
Get_Explorer_4:
} SizeLen = Code_ofs1 - Code_ofs0;
*CodeSize = SizeLen;
memcpy(aBuf,(void*)Code_ofs0,SizeLen);由于小弟汇编语言能力有限，恳请各位求助上述代码的含义，多谢．