怎么把一个字符串“3E9A”转换成十六进制数0x3E9A???谢谢！

Question

如题！

Answer 1

char* szText="3E9A";
int number=0;
sscanf(szText, "%X", &numbuer);assert(number == 0x3e9a);

Answer 2

CString strString=_T("3E9A");                      TCHAR* szStop=NULL;                      long nVal=0;                      nVal=_tcstol(strString,&szStop,16);

Answer 3

#include <iostream.h>
#include <assert.h>
void main( void )
{
char* szText="3E9A";
int number=0;
sscanf(szText, "%X", &number);
cout<<number<<endl;
cout<<hex<<number<<endl;
assert(number == 0x3e9a);
}
结果:
16026
3e9a

Answer 4

CString str = "3E9A";
int nRet = 0;
if(StrToIntEx("0x"+str, STIF_SUPPORT_HEX, &nRet))
{
TRACE("0x%x\n", nRet);
}