static void* operator new(size_t size);
static void operator delete(void* p);我定义的两个重载new,deletebase *b=new base;
delete b;//执行到这里怎么不调用重载的delete??这两个重载成对怎么定义才对?
static void operator delete(void* p);我定义的两个重载new,deletebase *b=new base;
delete b;//执行到这里怎么不调用重载的delete??这两个重载成对怎么定义才对?
http://lenux.blogchina.com/5180198.html
#define new DEBUG_NEW
#undef THIS_FILE
static char THIS_FILE[] = __FILE__;
#endif原来是这段惹的祸
Debug模式的new重新定义了~~
static void* operator new(size_t size,const char* szFile,int nLine);
这样才对,怪不得老出错
#ifdef _DEBUG
#define new DEBUG_NEW
#undef THIS_FILE
static char THIS_FILE[] = __FILE__;
#endif请问这段必需要的吗?不要行不行