或者来试试STL 里的string。//ret是一个向量,用来保存你的分词 while (i != s.size()) { // ignore leading blanks // invariant: characters in range `['original `i', current `i)' are all spaces while (i != s.size() && isspace(s[i])) ++i; // find end of next word string_size j = i; // invariant: none of the characters in range `['original `j', current `j)' is a space while (j != s.size() && !isspace(s[j])) ++j; // if we found some nonwhitespace characters if (i != j) { // copy from `s' starting at `i' and taking `j' `\-' `i' chars ret.push_back(s.substr(i, j - i)); i = j; } }
http://blog.csdn.net/freelybird/archive/2004/06/16/16489.aspx
while (i != s.size()) {
// ignore leading blanks
// invariant: characters in range `['original `i', current `i)' are all spaces
while (i != s.size() && isspace(s[i]))
++i; // find end of next word
string_size j = i;
// invariant: none of the characters in range `['original `j', current `j)' is a space
while (j != s.size() && !isspace(s[j]))
++j; // if we found some nonwhitespace characters
if (i != j) {
// copy from `s' starting at `i' and taking `j' `\-' `i' chars
ret.push_back(s.substr(i, j - i));
i = j;
} }