怎么样将_variant_t类型的数据转换为时间/日期型??急

Question

_variant_t birthday;
birthday=m_pRec->GetCollect ("birthday");
现在我要将birthday转化成为字符串CString 显示出来,2001-12-03的这种形式,怎么转换呢??

Answer 1

_variant_t birthday;
birthday=m_pRec->GetCollect ("birthday");
COleDateTime datBirthday(birthday);
CString sBirthday = datBirthday("%Y-%m-%d");

Answer 2

CString birthday;
birthday=(char *)(_bstr_t)m_pRec->GetCollect("birthday");

Answer 3

memory_xj(青蛙) 
不错！！！

Answer 4

呵呵，最后一句写错了：
CString sBirthday = datBirthday("%Y-%m-%d");应该是：
CString sBirthday = datBirthday.Format("%Y-%m-%d");

Answer 5

怎么不错啊??少了个Format()啊~~~~~

Answer 6

CString birthday;
birthday=(char *)(_bstr_t)m_pRec->GetCollect("birthday");

Answer 7

_variant_t birthday;
birthday=m_pRec->GetCollect ("birthday");
CString strBirthday = COleDateTime(birthday.date).Format("%Y-%m-%d");

Answer 8

char szDest[20];
sprintf(szDest,"%s",_bstr_t(birthday).operator const char*( ));

Answer 9

简单些:
char szDest[20];
strcpy(szDest,(char *)_bstr_t(birthday));