?
并且实际值是多少呢
并且实际值是多少呢
解决方案 »
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int main(int argc, char* argv[])
{
char *p;
float d; p=(char *) &d;
*(p++)=0x00;
*(p++)=0xa0;
*(p++)=0x91;
*(p++)=0x45;
printf("d:%f\n", d);
return 0;
}
Type double
Double precision values with double type have 8 bytes. The format is similar to the float format except that it has an 11-bit excess-1023 exponent and a 52-bit mantissa, plus the implied high-order 1 bit. This format gives a range of approximately 1.7E–308 to 1.7E+308 for type double.Microsoft Specific —>The double type contains 64 bits: 1 for sign, 11 for the exponent, and 52 for the mantissa. Its range is +/–1.7E308 with at least 15 digits of precision. END Microsoft Specific