如何阅读VC调试的反汇编 请问各位,VC调试的时候出现的反汇编怎么看,比如我的程序出现了内存泄漏,然后点调试出现出错的反汇编代码位置,我要怎么看 定位到程序的代码;这方面我是个新手 请各位多多指教 谢谢! 解决方案 » 免费领取超大流量手机卡,每月29元包185G流量+100分钟通话, 中国电信官方发货 1. 得懂ASM2. 可以试试call stack去定位到c++代码 这个容易,调试时在代码窗口的右键菜单中选择“Go To Disassembly”然后就是这样了:10: int main()11: {00401100 push ebp00401101 mov ebp,esp00401103 sub esp,6Ch00401106 push ebx00401107 push esi00401108 push edi00401109 lea edi,[ebp-6Ch]0040110C mov ecx,1Bh00401111 mov eax,0CCCCCCCCh00401116 rep stos dword ptr [edi]12: printf(" -- by MoreWindows( http://blog.csdn.net/MoreWindows ) --\n\n");00401118 push offset string " -- by MoreWindows( http://blog."... (0042202c)0040111D call printf (004015a0)00401122 add esp,413:14: const int MAXN = 10;00401125 mov dword ptr [ebp-4],0Ah15: int a[MAXN] = {2, 4, 1, 5, 7, 6, 1, 9, 0, 2};0040112C mov dword ptr [ebp-2Ch],200401133 mov dword ptr [ebp-28h],40040113A mov dword ptr [ebp-24h],100401141 mov dword ptr [ebp-20h],500401148 mov dword ptr [ebp-1Ch],70040114F mov dword ptr [ebp-18h],600401156 mov dword ptr [ebp-14h],10040115D mov dword ptr [ebp-10h],900401164 mov dword ptr [ebp-0Ch],00040116B mov dword ptr [ebp-8],2 http://blog.csdn.net/robertbaker/article/details/6362012 不过内存泄露还是用工具查快一些。如:Visual Leak Detector 谁有通过ffmpeg解码海康视频的程序阿 如何按照扫描行逐行提取位图数据? 窗口调用,很简单,来者有分!! 如何不让VS2003不自做主张? 求救!我的这段代码出现问题,功能是实现了Slider的透明显示, (在线等!)函数返回字符串时出错? error C2440: “类型转换” : 无法从“overloaded-function”转换为“LPTHREAD_START_ROUTINE”(急) 在线程里怎样得到主对话框的控件? RichEdit和CDialog的问题 请教WaitCommEvent的用法。 如何设计调用摄像头并可以拍照的界面,提供思路流程也可以 VC编写助手程序,类似VA那种
2. 可以试试call stack去定位到c++代码
然后就是这样了:10: int main()
11: {
00401100 push ebp
00401101 mov ebp,esp
00401103 sub esp,6Ch
00401106 push ebx
00401107 push esi
00401108 push edi
00401109 lea edi,[ebp-6Ch]
0040110C mov ecx,1Bh
00401111 mov eax,0CCCCCCCCh
00401116 rep stos dword ptr [edi]
12: printf(" -- by MoreWindows( http://blog.csdn.net/MoreWindows ) --\n\n");
00401118 push offset string " -- by MoreWindows( http://blog."... (0042202c)
0040111D call printf (004015a0)
00401122 add esp,4
13:
14: const int MAXN = 10;
00401125 mov dword ptr [ebp-4],0Ah
15: int a[MAXN] = {2, 4, 1, 5, 7, 6, 1, 9, 0, 2};
0040112C mov dword ptr [ebp-2Ch],2
00401133 mov dword ptr [ebp-28h],4
0040113A mov dword ptr [ebp-24h],1
00401141 mov dword ptr [ebp-20h],5
00401148 mov dword ptr [ebp-1Ch],7
0040114F mov dword ptr [ebp-18h],6
00401156 mov dword ptr [ebp-14h],1
0040115D mov dword ptr [ebp-10h],9
00401164 mov dword ptr [ebp-0Ch],0
0040116B mov dword ptr [ebp-8],2