怎样获得无模式对话框的句柄？

Question

也就是指向该对话框实例的指针

Answer 1

可以用
HWND FindWindow( 
LPCTSTR lpClassName, 
LPCTSTR lpWindowName ); 

Answer 2

#include "psapi.h"
#include "winbase.h"
HANDLE  GetProcessHD(char* ProcessName)
{
    DWORD aProcesses[1024], cbNeeded, cProcesses;
    char szProcessName[MAX_PATH] = "unknown";
    unsigned int i;
    if ( !EnumProcesses( aProcesses, sizeof(aProcesses), &cbNeeded ) )
        return  FALSE;
   cProcesses = cbNeeded / sizeof(DWORD);
    for ( i = 0; i < cProcesses; i++ )
{
        HANDLE hProcess = OpenProcess( PROCESS_QUERY_INFORMATION |
                                       PROCESS_VM_READ |
   PROCESS_TERMINATE,
                                       FALSE, aProcesses[i] );
        if (NULL != hProcess )
{
            HMODULE hMod;
            DWORD cbNeeded;
            if ( EnumProcessModules( hProcess, &hMod, sizeof(hMod), 
                                     &cbNeeded) )
{
                 GetModuleBaseName( hProcess, hMod, szProcessName, 
                                    sizeof(szProcessName) );
                 strupr(szProcessName);
 strupr(ProcessName);
 if(strcmp(szProcessName,ProcessName)==0)
 {
                                           return hProcess;
 }
}
            ;
}
        ;
DWORD b=GetLastError();
        CloseHandle( hProcess );
    }
    return FALSE;
}