怎样转换金额从数字到大写？

Question

怎样转换金额从数字到大写？谢谢！

Answer 1

void CTest2Dlg::OnOK() 
{
// TODO: Add extra validation here
float f  = 12345.25;
CString num[] =  {"零","壹","贰","叁","肆","伍","陆","柒","捌","玖"};
CString bit[] = {"","拾","佰","仟","万","亿"};
CString x,s,t;
int n;
s.Format ("%f",f);
int i = s.Find (".");
if ( i > 12 ) return;
i--;
for (int  j=0;j <= i;j++)
{
n = char(s.GetAt (i-j)) -48 ;
if ( j == 8) x = bit[5];
else x = bit[j%5];
t = num[n] + x + t;
}
t += "圆";
i = i+2;
n = char(s.GetAt (i)) -48 ;
t += num[n] + "角";
i++;
n = char(s.GetAt (i)) -48 ;
t += num[n] + "分";
m_strUp = t ;//m_strUP 是edit的string变量
UpdateData(FALSE);
}

Answer 2

#include <stdio.h>
#include <string.h>
const char* RMB(double rmb)
{
    if(rmb<0) return NULL;
static char *CCC[10]={ //Capital form of Chinese character
     "零","壹","贰","叁","肆","伍","陆","柒","捌","玖"
    };
    static char *QQQ[19]={"分","角",".","圆","拾","佰","仟","万","拾","佰","仟","亿",
     "拾","佰","仟","万","拾","佰","仟"
    };
    static char result[256],tmp[256];
    sprintf(tmp,"%.2lf",rmb);
    if(strlen(tmp)>19) return NULL;    int i=strlen(tmp)-1,c;
    char *srcPtr=tmp,*dstPtr=result;
    bool bPrevZero=false;
    for(; *srcPtr; srcPtr++,i--) {
     if(*srcPtr=='.') continue;
        c=*srcPtr-'0';
if(c!=0) {
         strcpy(dstPtr,CCC[c]); dstPtr+=2;
            if(srcPtr==tmp && c==1 && strcmp(QQQ[i],"拾")==0) dstPtr-=2;
        strcpy(dstPtr,QQQ[i]);  dstPtr+=2;
            bPrevZero=false;
            continue;
        }        if(bPrevZero) {
         if(strcmp(QQQ[i],"圆")==0 || strcmp(QQQ[i],"万")==0 || strcmp(QQQ[i],"亿")==0) {
             dstPtr-=2; *dstPtr=0;
             if(strcmp(dstPtr-2,"亿")) {strcpy(dstPtr,QQQ[i]); dstPtr+=2;}
                bPrevZero=false;
            }
        } else {
         if(strcmp(QQQ[i],"圆") && strcmp(QQQ[i],"万") && strcmp(QQQ[i],"亿")) {
strcpy(dstPtr,"零"); dstPtr+=2;
                bPrevZero=true;
            }else {
             strcpy(dstPtr,QQQ[i]);  dstPtr+=2;
                bPrevZero=false;
            }
}
    }    i=strlen(result);
    if(strcmp(result+i-2,"零")==0) result[i-2]=0;
    tmp[0]=result[0]; tmp[1]=result[1]; tmp[2]=0;
    if(strcmp(tmp,"圆")==0) {
        if(result[2]==0) strcpy(result,"零圆");
        else {
         tmp[0]=result[2]; tmp[1]=result[3]; tmp[2]=0;
            return strcmp(tmp,"零")==0 ? result+4 : result+2 ;
        }
    }
    return result;
}

Answer 3

需要改动：
1、CString bit[] = {"万","拾","佰","仟","亿",""};
2、if ( j== 0 ) x = bit[5];
else if ( j == 8) x = bit[4];
else x = bit[j%4];
3、double f  = 1234567890.25;