怎么生成一个标准的单色位图呢？

不好意思，不太理解你这个，还能具体点吗？网上搜了一大堆都是生成的biBitCount=24的位图，方法也不尽相同，我写的dll需要调用这个函数生成一个单色位图的int Down_Bitmap(char *BitmapName,int Width,int Height,char *BitmapData)BitmapName，生成图的名字，BitmapData位图数据

函数原型：HBITMAP CreateBitmap(int nWidth,int nHeight, UINT cPlanes, UINT cBitsPeral,CONST VOID *lpvBits)；
参数：
nWidth：指定位图宽度、单位为像素。
nHeight：指定位图高度、单位为像素。
CPlanes：指定该设备使用的颜色位面数目。
CBitsPerPel：指定用来区分单个像素点颜色的位数（比特数目）。
LpvBits：指向颜色数据数组指针。这些颜色数据用来设置矩形区域内像素的颜色。矩形区域中的每一扫描线必须是双字节的整数倍（不足部分以0填充）。如果该参数为NULL，将不对新生成的位图进行初始化。
返回值：如果函数成功，那么返回值是位图的句柄；如果失败，那么返回值为NULL。若想获取更多错误信息，请调用GetLastError函数。
红色的 2个 1,1 就是

谢谢了，以前从来没有做过GDI，hdcDest和hImageDC分别怎么来的呢？创建好之后怎么保存到某个路径呢？

int Down_Bitmap(char *BitmapName,int Width,int Height,char *BitmapData)
{
CBitmap bmpNew;
  BOOL bRet = bmpNew.CreateBitmap(Width, Height, 1, 1, BitmapData);
  if(bRet)
  {
  TRACE(_T("OK"));   }
else
{ TRACE(_T("False"));
}
BITMAP bmNew;
bmpNew.GetBitmap(&bmNew);
char szFileName[32];
sprintf(szFileName, "c:/%04d.bmp",BitmapName);
FILE* fBmp = fopen(szFileName, "wb");
BITMAPFILEHEADER bmHead;
ZeroMemory(&bmHead, sizeof(bmHead)); bmHead.bfSize = sizeof(bmHead);
bmHead.bfType = 0x4d42;
bmHead.bfOffBits = sizeof(BITMAPFILEHEADER) + sizeof(BITMAPINFOHEADER); fwrite(&bmHead, sizeof(bmHead), 1, fBmp); BITMAPINFOHEADER bmpInfo;
ZeroMemory(&bmpInfo, sizeof(bmpInfo));
bmpInfo.biSize = sizeof(bmpInfo);
bmpInfo.biWidth = bmNew.bmWidth;
bmpInfo.biHeight = bmNew.bmHeight;
bmpInfo.biPlanes = bmNew.bmPlanes;
bmpInfo.biBitCount = bmNew.bmBitsPixel;
bmpInfo.biSizeImage = ((bmNew.bmWidth * bmNew.bmBitsPixel) + 7) / 8 * bmNew.bmHeight;
BYTE* pData = new BYTE[bmpInfo.biSizeImage];
   bmpNew.GetBitmapBits(bmpInfo.biSizeImage, (LPVOID)pData);
   fwrite(pData, bmpInfo.biSizeImage, 1, fBmp);
   delete []pData;
   fclose(fBmp);
}
这么调用的char BitmapName[5]={'0','0','0','1','\0'};
char BitmapData[50]={0xff};
Down_Bitmap(BitmapName,30,50,BitmapData);
大家帮我看看写的代码哪里有不对的地方吗？谢谢

char BitmapName[6]="00010";
char BitmapData[500000]={0};
int ret=Down_Bitmap(BitmapName,30,50,BitmapData);

sprintf(szFileName, "C://%04s.bmp",BitmapName); BitmapName=0001
HBITMAP bmpball,bmpBk;
bmpball = (HBITMAP)LoadImage( NULL, (LPCWSTR)szFileName, IMAGE_BITMAP, 0, 0,
LR_CREATEDIBSECTION | LR_DEFAULTSIZE | LR_LOADFROMFILE );
总是加载图片失败，GetLastError()=2，找不到文件

现在我生成的单色bmp不是全白的背景，怎么生成全白背景呢？

你不是 “LoadImage” 的吗？
怎么又是 Create ？

先生成一个单色的白板bmp，然后才加载获取的，loadimage的问题解决了，现在发现生成的白板bmp有点问题？不知道哪里出错了，麻烦帮我看看。下面是代码：
int creatBMP()
{
CBitmap bmpNew;
  BOOL bRet = bmpNew.CreateBitmap(640, 384, 1, 1, NULL); /*memDC.SelectObject(bmpNew);
memDC.SetBkColor(RGB(0, 244, 0));
memDC.TextOut(0, 0, _T("AAA"));
memDC.LineTo(10, 10);*/ BITMAP bmNew;
bmpNew.GetBitmap(&bmNew);
FILE* fBmp = fopen("D:\\back.bmp", "wb");

int widthbytes  = (int)((bmNew.bmWidth*bmNew.bmBitsPixel+31)/32)*4;
BITMAPFILEHEADER bmHead;
ZeroMemory(&bmHead, sizeof(bmHead));
bmHead.bfType = 0x4d42;
//bmHead.bfOffBits = sizeof(BITMAPFILEHEADER) + sizeof(BITMAPINFOHEADER);
bmHead.bfOffBits =(DWORD)(sizeof(BITMAPFILEHEADER) + sizeof(BITMAPINFOHEADER) + 2*4);
//bmHead.bfSize = sizeof(bmHead);
bmHead.bfSize=(DWORD)(bmHead.bfOffBits + bmNew.bmHeight * widthbytes);
fwrite(&bmHead, sizeof(bmHead), 1, fBmp); BITMAPINFOHEADER bmpInfo;
ZeroMemory(&bmpInfo, sizeof(bmpInfo));
bmpInfo.biSize = sizeof(bmpInfo);
bmpInfo.biWidth = bmNew.bmWidth;
bmpInfo.biHeight = bmNew.bmHeight;
bmpInfo.biPlanes = bmNew.bmPlanes;
bmpInfo.biBitCount = bmNew.bmBitsPixel;
bmpInfo.biSizeImage = bmNew.bmHeight * widthbytes; fwrite(&bmpInfo, sizeof(bmpInfo), 1, fBmp); BYTE* pData = new BYTE[bmpInfo.biSizeImage];
   bmpNew.GetBitmapBits(bmpInfo.biSizeImage, (LPVOID)pData);
   for(int i=0;i<bmpInfo.biSizeImage;i++)
   {
   pData[i]=0xff;
   }//这里给图形数据都赋成1来显示白板，这样不知道行不行？还是有其他的方法？
   fwrite(pData, bmpInfo.biSizeImage, 1, fBmp);    delete []pData;
   fclose(fBmp);
   return 1;
}

for(int i=0;i<bmpInfo.biSizeImage;i++)
   {
   pData[i]=0xff;
   }memset(pData,0xFF,bmpInfo.biSizeImage)

这两个有区别吗？这样的方式生成的白板图片可用吗？因为后面我还要加载这个白板然后把一个小图片贴上去，现在出现的问题是把小图片贴在我自己生成的这个图片上看不见，而从其他地方找来的图片就能看见，这啥问题？上面的那段代码有问题吗？
bmHead.bfType = 0x4d42;
//bmHead.bfOffBits = sizeof(BITMAPFILEHEADER) + sizeof(BITMAPINFOHEADER);
bmHead.bfOffBits =(DWORD)(sizeof(BITMAPFILEHEADER) + sizeof(BITMAPINFOHEADER) + 2*4);
//bmHead.bfSize = sizeof(bmHead);
bmHead.bfSize=(DWORD)(bmHead.bfOffBits + bmNew.bmHeight * widthbytes);
fwrite(&bmHead, sizeof(bmHead), 1, fBmp);BITMAPINFOHEADER bmpInfo;
ZeroMemory(&bmpInfo, sizeof(bmpInfo));
bmpInfo.biSize = sizeof(bmpInfo);
bmpInfo.biWidth = bmNew.bmWidth;
bmpInfo.biHeight = bmNew.bmHeight;
bmpInfo.biPlanes = bmNew.bmPlanes;
bmpInfo.biBitCount = bmNew.bmBitsPixel;
bmpInfo.biSizeImage = bmNew.bmHeight * widthbytes;这段到底对不对呢？找了很多资料整成这样的，不过还是不确定

// If the bitmap is monochrome, the bmiColors member contains two entries.
// Each bit in the bitmap array represents a pixel.
// If the bit is clear, the pixel is displayed with the color of the first entry in the bmiColors table;
// if the bit is set, the pixel has the color of the second entry in the table.
int creatBMP()
{
CBitmap bmpNew;
BOOL bRet = bmpNew.CreateBitmap(640, 384, 1, 1, NULL); BITMAP bmNew;
bmpNew.GetBitmap(&bmNew);
FILE* fBmp = fopen("back.bmp", "wb"); int widthbytes  = (int)((bmNew.bmWidth*bmNew.bmBitsPixel+31)/32)*4;
BITMAPFILEHEADER bmHead;
ZeroMemory(&bmHead, sizeof(bmHead));
bmHead.bfType = 0x4d42;
bmHead.bfOffBits =(DWORD)(sizeof(BITMAPFILEHEADER) +
                      sizeof(BITMAPINFOHEADER) +
  2*sizeof(RGBQUAD));
bmHead.bfSize=(DWORD)(bmHead.bfOffBits + bmNew.bmHeight * widthbytes);
// write BITMAPFILEHEADER
fwrite(&bmHead, sizeof(bmHead), 1, fBmp);
//
BITMAPINFOHEADER bmpInfo;
ZeroMemory(&bmpInfo, sizeof(bmpInfo));
bmpInfo.biSize      = sizeof(bmpInfo);
bmpInfo.biWidth     = bmNew.bmWidth;
bmpInfo.biHeight = bmNew.bmHeight;
bmpInfo.biPlanes = bmNew.bmPlanes;
bmpInfo.biBitCount = bmNew.bmBitsPixel;
bmpInfo.biSizeImage = bmNew.bmHeight * widthbytes;
// write BITMAPINFOHEADER
fwrite(&bmpInfo, sizeof(bmpInfo), 1, fBmp);
RGBQUAD  bmiColors[2]={{0,0,0,0},{0xFF,0xFF,0xFF,0}}; // white
// if exchange these
// RGBQUAD  bmiColors[2]={{0xFF,0xFF,0xFF,0},{0,0,0,0}}; // black
fwrite(bmiColors, 2*sizeof(RGBQUAD), 1, fBmp);
// write pallete
BYTE* pData = new BYTE[bmpInfo.biSizeImage];
bmpNew.GetBitmapBits(bmpInfo.biSizeImage, (LPVOID)pData);
memset(pData,0xFF,bmpInfo.biSizeImage);
fwrite(pData, bmpInfo.biSizeImage, 1, fBmp);
//
delete []pData;
fclose(fBmp);
return 1;
}、
注意：
RGBQUAD  bmiColors[2]={{0,0,0,0},{0xFF,0xFF,0xFF,0}}; // white
// if exchange these
// RGBQUAD  bmiColors[2]={{0xFF,0xFF,0xFF,0},{0,0,0,0}}; // black
fwrite(bmiColors, 2*sizeof(RGBQUAD), 1, fBmp);

谢谢你的回答，调色板弄好了，现在有一个问题
char BitmapData[60]={0xE0,0x7E,0x00,0x00,0xE0,0x7E,0x00,0x00,0xE0,0x7E,0x00,0x00,0xFC,0x7E,0x00,0x00,0xFC,0x7E,0x00,0x00,0xFC,0x7E,0x00,0x00,0xFC,0x7E,0x00,0x00,0xFC,0x7E,0x00,0x00,0xFC,0x7E,0x00,0x00,0xE0,0x00,0x00,0x00,0xE0,0x00,0x00,0x00,0xE0,0x00,0x00,0x00,0xFF,0xFE,0x00,0x00,0xFF,0xFE,0x00,0x00,0xFF,0xFE,0x00,0x00};
Down_Bitmap(BitmapName,15,15,BitmapData);
我这样传入数据想显示一个“丁”字，可是查看二值化数据只写进去前30位，红色表示的字节，后面30位全是CD，怎么回事呢？

没看到 “Down_Bitmap(BitmapName,15,15,BitmapData);”函数15（2个字节一行） ,15（共 15行） = 2 bytes *15= 30 个字节

真是多谢你了，我用下面代码旋转位图有一个问题，旋转45度可以，旋转90度两边就多了两条线。
HDC RotateAnyAngle(HDC dcSrc,int SrcWidth,int SrcHeight,double angle)
{
double x1,x2,x3;
double y1,y2,y3;
double maxWidth,maxHeight,minWidth,minHeight;
double srcX,srcY;
double sinA,cosA;
double DstWidth;
double DstHeight;
HDC dcDst;//旋转后的内存设备环境
HBITMAP newBitmap;
sinA = sin(angle);
cosA = cos(angle);
x1 = -SrcHeight * sinA;
y1 = SrcHeight * cosA;
x2 = SrcWidth * cosA - SrcHeight * sinA;
y2 = SrcHeight * cosA + SrcWidth * sinA;
x3 = SrcWidth * cosA;
y3 = SrcWidth * sinA;
minWidth = x3>(x1>x2?x2:x1)?(x1>x2?x2:x1):x3;
minWidth = minWidth>0?0:minWidth;
minHeight = y3>(y1>y2?y2:y1)?(y1>y2?y2:y1):y3;
minHeight = minHeight>0?0:minHeight;
maxWidth = x3>(x1>x2?x1:x2)?x3:(x1>x2?x1:x2);
maxWidth = maxWidth>0?maxWidth:0;
maxHeight = y3>(y1>y2?y1:y2)?y3:(y1>y2?y1:y2);
maxHeight = maxHeight>0?maxHeight:0;
DstWidth = maxWidth - minWidth;
DstHeight = maxHeight - minHeight;
dcDst = CreateCompatibleDC(dcSrc);
newBitmap = CreateCompatibleBitmap(dcSrc,(int)DstWidth,(int)DstHeight);
SelectObject(dcDst,newBitmap);
for( int I = 0 ;I<DstHeight;I++)
{
for(int J = 0 ;J< DstWidth;J++)
{
srcX = (J + minWidth) * cosA + (I + minHeight) * sinA;
srcY = (I + minHeight) * cosA - (J + minWidth) * sinA;
if( (srcX >= 0) && (srcX <= SrcWidth) &&(srcY >= 0) && (srcY <= SrcHeight))
{
BitBlt(dcDst, J, I, 1, 1, dcSrc,(int)srcX, (int)srcY, SRCCOPY);
}
}
} //显示旋转后的位图
HDC pDC = ::GetDC(AfxGetMainWnd()->m_hWnd);
//CDC*pDC=GetDC();
HDC hThisDC=CDC::FromHandle(pDC)->GetSafeHdc();
BitBlt(hThisDC,40,40,(int)DstWidth,(int)DstHeight,dcDst,0,0,SRCCOPY);
return dcDst;
DeleteObject(newBitmap);
DeleteDC(dcDst);

}
angle= (45/180.0)*3.14159;//旋转45Degree,可为任意角度
RhBkDC=RotateAnyAngle(hBkDC,640,384,angle);

调试易

怎么生成一个标准的单色位图呢？

解决方案 »