十万火急：大虾们帮帮忙啊。有点小程序调不通 ｈｅｌｐ。。。

Question

char   num[]   ={num0,num1,num2,num3};
num0\num1\num2\num3都是char[5]的数组,
可定义num为指针数组或直接定义二维数组

Answer 1

#define   num0  0x25,0x48,0x77,0x34,0x55 
...char   num[]   ={num0,num1,num2,num3}; 

Answer 2

char*   num[]   ={num0,num1,num2,num3}; 应该可以了就

Answer 3

#include "stdafx.h"
#include   <iostream.h>
void   main()
{
char   num0[]   ={0x25,0x48,0x77,0x34,0x55};
char   num1[]   ={0x25,0x48,0x77,0x34,0x55};
char   num2[]   ={0x25,0x48,0x77,0x34,0x55};
char   num3[]   ={0x25,0x48,0x77,0x34,0x55};
char   *num[]   ={num0,num1,num2,num3};} 

Answer 4

#include "stdafx.h"
#include   <iostream.h>
#include <conio.h>
void   main()
{
char   num0[]   ={0x25,0x48,0x77,0x34,0x55};
char   num1[]   ={0x25,0x48,0x77,0x34,0x55};
char   num2[]   ={0x25,0x48,0x77,0x34,0x55};
char   num3[]   ={0x25,0x48,0x77,0x34,0x55};
char*   num[]   ={num0,num1,num2,num3};
printf("%02x", num[0][2]);
getch();
}