如何响应KeyPress消息

Question

只能用测试键盘状态的API来得到状态，
不知道MFC有无封装。

Answer 1

如果一治按着健的话,并不是只发出一个Keydown,然后等待你松开才发出Keyup.而是连续发出几对Keydown和Keyup,而且是成对的,最后一个Keyup.然后就停止掉.所以一会儿以后就不响应了.

Answer 2

sorry,刚才我用spy++测试过了,证明我的理解错了..

Answer 3

这是我一个检测按钮的模块，里面的上下左右是连续判断，而其她的是判断一次，
这个程序可以和其它流程一起执行不影响。// 检测坦克1P按键
void Key1PT(void)
{
int st=16;
int Zd=0;
int xx1,yy1;
    Tank1.old_y=Tank1.y;Tank1.old_x=Tank1.x;
xx1=Tank1.x;yy1=Tank1.y;
if( GetAsyncKeyState(VK_DOWN)  ) //下
{
Tank1.old_y=Tank1.y;
Tank1.y+=Tank1.speed;
Tank1.fx=3;
Tank1.x=Tank1.x-Tank1.x%st;
            Tank1.old_x=Tank1.x;
goto Key1PE;
}
if( GetAsyncKeyState(VK_UP)  ) //上
{
Tank1.old_y=Tank1.y;
Tank1.y-=Tank1.speed;
Tank1.fx=2;
Tank1.x=Tank1.x-Tank1.x%st;
            Tank1.old_x=Tank1.x;
goto Key1PE;
}
if( GetAsyncKeyState(VK_LEFT)  ) //左
{
Tank1.old_x=Tank1.x;
Tank1.x-=Tank1.speed;
Tank1.fx=0;
Tank1.y=Tank1.y-Tank1.y%st;
            Tank1.old_y=Tank1.y;
goto Key1PE;
}
if( GetAsyncKeyState(VK_RIGHT)  )   //右
{
Tank1.old_x=Tank1.x;
Tank1.x+=Tank1.speed;
Tank1.fx=1;
Tank1.y=Tank1.y-Tank1.y%st;
            Tank1.old_y=Tank1.y;
goto Key1PE;
}
Key1PE:
        //普通子弹
if( (GetAsyncKeyState(VK_DELETE)) ||   //DELETE
(GetAsyncKeyState(VK_RETURN) ||    //回车
(GetAsyncKeyState(VK_SPACE) 
{
//while(GetAsyncKeyState(VK_DELETE)) {}
}
        if(GetAsyncKeyState(VK_DELETE)==FALSE) Tank1PP=0;
if(GetAsyncKeyState(VK_RETURN)==FALSE) Tank1PP1=0;
if(GetAsyncKeyState(VK_SPACE)==FALSE) Tank1PP2=0;}

Answer 4

这样试试看,应该可以了吧
BOOL CDlgDlg::PreTranslateMessage(MSG* pMsg) 
{ if(pMsg->message == WM_KEYDOWN)
{
if((pMsg->lParam & 0x00ff) ==1)
SetTimer();
} if(pMsg->message ==WM_KEYUP)
KillTimer();

return CDialog::PreTranslateMessage(pMsg);
}