怎样操作这个xml 文档啊

Question

<?xml version="1.0" encoding="gb2312"?>
<root>
     <message id="1" desc="mainStationParamSet"/>
     <param> 
           <backupParam value="no"/>
           <serialNum value="0"/>
           <Interval value="0"/>
           <cableCount value="1"/>
           <subStationCount value="0"/>
           <cableParam>
              <cable startip="0" xiangxian="0"/>              
           </cableParam>
       </param>
</root>我想改变 backupParam 、Interval  等的值

Answer 1

可以通过
dataset
xmldocument
xmlreader xmlwriter
进行操作

Answer 2

我向用xmldocument操作，可是不成功。 能给个简单的代码吗

Answer 3

XmlDocument doc = new XmlDocument();
doc.Load(path);
XmlNode backupParam = doc.SelectSingleNode("/root/param/backupParam");
XmlNode interval = doc.SelectSingleNode("/root/param/Interval");
得到节点后改写attribute
然后doc.Save(path);

Answer 4

backupParam.Attributes["value"].Value = "";
interval.Attributes["value"].Value = "";

Answer 5

也可以读成数据表再修改保存
dataset.readXml();
dataset.writeXml();

Answer 6

backupParam .innertext="XXX";
doc.save();