因为有40个string变量
lup1........lup20
nup1........nup20有个地方需要nup的值对应的赋到lup中
lup1:=nup1;lup2:=nup2;...............lup20:=nup20; 但用
for i:=1 to 20 do
begin
('lup'+IntToStr(i)):=('nup'+IntToStr(i));
end;
就不行,说Left Side Cannot be assinged to
请问有解决的办法吗?
lup1........lup20
nup1........nup20有个地方需要nup的值对应的赋到lup中
lup1:=nup1;lup2:=nup2;...............lup20:=nup20; 但用
for i:=1 to 20 do
begin
('lup'+IntToStr(i)):=('nup'+IntToStr(i));
end;
就不行,说Left Side Cannot be assinged to
请问有解决的办法吗?
var
lup:array[1..20] of string;
nup:array[1..20] of string;
i:integer;
-----------------------------------for i:=1 to 20 do
begin
...
lup[i]:=nup[i];
...
end;