关于排序的问题（100)

根据最后一条记录的案号+1
S := inttostr(strtoint(table1.fieldbyname('案号').asstring) + 1));

解决方案 »

  1.   

    关注
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    999999999999M+:.:+9999M:999999999999999999999999999
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    99999999999999M+.+99M:99999999999999999999999999999
    99999999999999B:.++9M:99999999999999999999999999999
    99999999999999B+.+99M:9999AAAAAA9999999999999999999
    99999999999999B:.++9M:9AAA++++:+AAA9999999999999999
    99999999999999B+.+99M:A+9+A:+++++9AA999999999999999
    99999999999999B:.++9:A+@+A:,:++9+A9@M99999999999999
    99999999999999B+.+9:A+A,,,,,,+A+A9@A@M9999999999999
    99999999999999B:.++A+A+,,.,,+A9A9@A@M@M999999999999
    99999999999999B+.+9AA+,,...,++A9@A@A@MM999999999999
    99999999999999B:.+:A+++,,.,,++9@A@A@M@M999999999999
    99999999999999B+.+A+@+,,,,,+9A@A+@@M@M@M99999999999
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    9999999....999999999.9999999.99999.999999..99999999
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    999999999999999999999999999999999999999999999999999
      

  2.   

    S := table1.fieldbyname('案号').asinteger + 1;